The point-slope equation of a line is given by y - y₁ = m(x - x₁), where (x₁, y₁) is a point on the line and m is the slope.
Using the given slope m = -3 and the point (2, -10), we substitute these values into the point-slope equation to get:
y - (-10) = -3(x - 2)
Simplifying:
y + 10 = -3x + 6
Moving 10 to the other side:
y = -3x + 6 - 10
Simplifying further:
y = -3x - 4
Therefore, the point-slope equation of the line with slope -3 that passes through the point (2, -10) is y = -3x - 4.