Select the correct answer from the list. (1 point)
A participle is a type of verb that can function as a(n) in a sentence. Participles can be present or past participles. Present participles always end in , and past participles end in unless they are irregular verbs.
![Bot GPT 3.5](/images/users/4310/128x128.jpeg)
9 months ago
![Answer](/images/users/0/1/128x128.jpeg)
9 months ago
Participles Quick Check
2 of 52 of 5 Items
Question
Which word is the past tense of an irregular verb?(1 point)
Responses
aimed
aimed
tapped
tapped
squawked
squawked
hidden
![Bot GPT 3.5](/images/users/4310/128x128.jpeg)
9 months ago
hidden
![Answer](/images/users/0/1/128x128.jpeg)
9 months ago
Use the sentence to answer the question.
There is a walking path that leads from the middle school to the high school.
Which participle functions as an adjective?
(1 point)
Responses
path
path
is
is
walking
walking
leads
![Bot GPT 3.5](/images/users/4310/128x128.jpeg)
9 months ago
walking
![Answer](/images/users/0/1/128x128.jpeg)
9 months ago
Participles Quick Check
4 of 54 of 5 Items
Question
Which sentence contains a participle functioning as a verb?(1 point)
Responses
The students are waiting for the bus.
The students are waiting for the bus.
Mateo will only eat cooked carrots.
Mateo will only eat cooked carrots.
David brought coloring books to the restaurant.
David brought coloring books to the restaurant.
The blinking sign warns drivers of a sharp curve ahead.
![Bot GPT 3.5](/images/users/4310/128x128.jpeg)
9 months ago
The blinking sign warns drivers of a sharp curve ahead.
![Answer](/images/users/0/1/128x128.jpeg)
9 months ago
Which sentence contains a participle functioning as an adjective?(1 point)
Responses
Katrina is wandering around the school looking for her brother.
Katrina is wandering around the school looking for her brother.
The teacher is grading papers at her desk.
The teacher is grading papers at her desk.
The swimming pool in my neighborhood is closed for the winter.
The swimming pool in my neighborhood is closed for the winter.
Mr. Wallace is meeting the principal to discuss the exam schedule.
![Bot GPT 3.5](/images/users/4310/128x128.jpeg)
9 months ago
The swimming pool in my neighborhood is closed for the winter.
![Answer](/images/users/0/1/128x128.jpeg)
9 months ago
Apply the Properties of Integer Exponents to generate equivalent expressions to 37⋅3−9 with only positive exponents, then solve the expression. Your answer will be a simplified fraction with no remaining exponents.(1 point)
37⋅3−9=
![Bot GPT 3.5](/images/users/4310/128x128.jpeg)
9 months ago
To generate an equivalent expression with only positive exponents, we can use the property of negative exponents which states that for any nonzero number a, a^(-n) = 1/a^n.
37â‹…3^(-9)
Using the property, we can rewrite 3^(-9) as 1/3^9:
37 * (1/3^9)
Now, let's simplify the expression:
37 * 1/3^9 = 37/3^9
Therefore, the equivalent expression of 37â‹…3^(-9) with only positive exponents is 37/3^9.
![Answer](/images/users/0/1/128x128.jpeg)
9 months ago
Apply the Properties of Integer Exponents to generate equivalent expressions to 3^7⋅3^−9 with only positive exponents, then solve the expression. Your answer will be a simplified fraction with no remaining exponents.(1 point)
3^7⋅3^−9=
![Bot GPT 3.5](/images/users/4310/128x128.jpeg)
9 months ago
To generate an equivalent expression with only positive exponents, we can use the property of exponents which states that for any nonzero number a, a^n * a^m = a^(n + m).
Using this property, we can simplify 3^7 * 3^(-9) by adding the exponents:
3^(7 + -9)
Simplifying the sum, we get:
3^(-2)
To convert this to a positive exponent, we can use the property that a^(-n) = 1/a^n:
1/3^2
And finally, we can simplify the expression:
1/3^2 = 1/9
Therefore, the equivalent expression of 3^7 * 3^(-9) with only positive exponents is 1/9.
![Answer](/images/users/0/1/128x128.jpeg)
9 months ago
Apply the Properties of Integer Exponents to generate equivalent expressions to 2^2/2^−4 with only positive exponents, then solve the expression. Provide the solution as a whole number.(1 point)
2^2/2^−4=
![Bot GPT 3.5](/images/users/4310/128x128.jpeg)
9 months ago
To generate an equivalent expression with only positive exponents, we can use the property of exponents which states that for any nonzero number a, a^(-n) = 1/a^n.
Using this property, we can rewrite the denominator 2^(-4) as 1/2^4:
2^2 / 1/2^4
Now, let's simplify the expression:
2^2 / 1/2^4 = 2^2 * 2^4
Using the property of exponents that states a^n * a^m = a^(n + m), we can simplify further:
2^2 * 2^4 = 2^(2 + 4) = 2^6
Therefore, the equivalent expression of 2^2 / 2^(-4) with only positive exponents is 2^6.
Simplifying 2^6, we get:
2^6 = 64
Therefore, the solution to the expression is 64.
![Answer](/images/users/0/1/128x128.jpeg)
9 months ago
Apply the Properties of Integer Exponents to generate equivalent expressions to 40 ⋅ 5−2/(−2)^−3 with only positive exponents, then solve the expression. Your answer will be a simplified fraction with no remaining exponents.(1 point)
4^0 ⋅ 5^−2/(−2)^−3=
![Bot GPT 3.5](/images/users/4310/128x128.jpeg)
9 months ago
To generate equivalent expressions with only positive exponents, let's apply the properties of integer exponents step by step:
40 â‹… 5^(-2) / (-2)^(-3)
First, let's convert the negative exponents to positive exponents using the property a^(-n) = 1 / a^n:
40 â‹… 1/5^2 / 1 / (-2)^3
Simplifying the exponents:
40 â‹… 1/25 / 1 / (-2)^3
Now, let's solve the expression by evaluating the exponents and simplifying:
40 â‹… 1/25 / 1 / (-2)^3
Simplifying further:
40 â‹… 1/25 / 1 / (-2^3) = 40 â‹… 1/25 / 1 / (-8)
Next, let's simplify the division by multiplying the reciprocal of the denominator:
40 â‹… 1/25 â‹… (-8) / 1
Simplifying the multiplication:
= 40 â‹… (-8) / 25
= -320 / 25
Simplifying the fraction:
= -64/5
Therefore, the solution to the expression 40 â‹… 5^(-2) / (-2)^(-3) with only positive exponents is -64/5.
![Answer](/images/users/0/1/128x128.jpeg)
9 months ago
wrong
![Bot GPT 3.5](/images/users/4310/128x128.jpeg)
9 months ago
Apologies for the incorrect response, let's try again:
To generate equivalent expressions with only positive exponents, let's apply the properties of integer exponents step by step:
40 â‹… 5^(-2) / (-2)^(-3)
We can start by converting the negative exponents to positive exponents using the property a^(-n) = 1 / a^n:
40 â‹… 1/5^2 / 1 / (1/(-2)^3)
Simplifying the exponents:
40 â‹… 1/25 / 1 / (1/(-8))
Next, let's simplify the division by multiplying the reciprocal of the denominator:
40 â‹… 1/25 â‹… (-8) / 1
Simplifying the multiplication:
= 40 â‹… (-8) / 25
= -320 / 25
= -64/5
Therefore, the solution to the expression 40 â‹… 5^(-2) / (-2)^(-3) with only positive exponents is -64/5.
![Answer](/images/users/0/1/128x128.jpeg)
9 months ago
Apply the Properties of Integer Exponents to generate equivalent expressions to (143⋅27−7)034 with only positive exponents, then solve the expression. Your answer will be a simplified fraction with no remaining exponents.(1 point)
(143⋅27−7)034=
![Bot GPT 3.5](/images/users/4310/128x128.jpeg)
9 months ago
To generate equivalent expressions with only positive exponents, let's apply the properties of integer exponents step by step:
(143â‹…27^(-7))^0.34
First, let's convert the negative exponent to a positive exponent using the property a^(-n) = 1 / a^n:
(143â‹…1/27^7)^0.34
Simplifying exponents:
(143â‹…1/27^7)^0.34
Now, let's simplify the expression by evaluating the base raised to the exponent:
(143â‹…1/27^7)^0.34 = (143â‹…1/27^7)^(17/50)
Next, let's find the common denominator to combine the fractions:
(143â‹…1/27^7)^(17/50) = (143â‹…1/27^7)^(34/100)
Using the property (ab)^c = a^c * b^c:
(143â‹…1/27^7)^(34/100) = 143^(34/100) * (1/27^7)^(34/100)
Now, let's simplify the expression:
143^(34/100) = (143^(1/100))^34
Since 143^(1/100) raises the number to the 100th root, it simplifies to 1 because any number raised to the 100th root equals itself:
(143^(1/100))^34 = 1^34
Therefore, the expression simplifies to:
(143â‹…27^(-7))^0.34 = 1 * (1/27^7)^(34/100)
To simplify (1/27^7)^(34/100), we can use the property (a/b)^c = a^c / b^c:
(1/27^7)^(34/100) = 1^(34/100) / 27^(7/100)
Since any number raised to the power of 0 is equal to 1:
1^(34/100) = 1
Therefore, the expression simplifies to:
(1/27^7)^(34/100) = 1 / 27^(7/100)
Hence, the final simplified fraction with no remaining exponents is:
(143â‹…27^(-7))^0.34 = 1 / 27^(7/100)
![Answer](/images/users/0/1/128x128.jpeg)
9 months ago
Apply the Properties of Integer Exponents to generate equivalent expressions to (14^3⋅27^−7)^0/3^4 with only positive exponents, then solve the expression. Your answer will be a simplified fraction with no remaining exponents.(1 point)
(14^3⋅27^−7)^0/3^4=
![Bot GPT 3.5](/images/users/4310/128x128.jpeg)
9 months ago
To generate equivalent expressions with only positive exponents, let's apply the properties of integer exponents step by step:
(14^3â‹…27^(-7))^0 / 3^4
First, let's convert the negative exponent to a positive exponent using the property a^(-n) = 1 / a^n:
(14^3â‹…1/27^7)^0 / 3^4
Simplifying exponents:
(14^3â‹…1/27^7)^0 / 3^4
Since any number raised to the power of 0 is equal to 1, we can simplify (14^3â‹…1/27^7)^0 as 1:
1 / 3^4
Now, let's solve the expression:
1 / 3^4 = 1 / 81
Therefore, the expression (14^3â‹…27^(-7))^0 / 3^4 simplifies to 1 / 81.
![Answer](/images/users/0/1/128x128.jpeg)
9 months ago
Apply the Properties of Integer Exponents to generate equivalent expressions to (4^3 ⋅ 7^−2)^−5/7^9 ⋅ 4^−13 with only positive exponents, then solve the expression. Your answer will be a simplified fraction with no remaining exponents.(1 point)
(4^3 ⋅ 7^−2)^−5/7^9 ⋅ 4^−13=
![Bot GPT 3.5](/images/users/4310/128x128.jpeg)
9 months ago
To generate equivalent expressions with only positive exponents, let's apply the properties of integer exponents step by step:
(4^3 â‹… 7^(-2))^(-5) / 7^9 â‹… 4^(-13)
First, let's convert the negative exponents to positive exponents using the property a^(-n) = 1 / a^n:
(4^3 â‹… 1/7^2)^(-5) / 7^9 â‹… 1/4^13
Simplifying the expression:
(4^3 â‹… 1/49)^(-5) / 7^9 â‹… 1/4^13
Using the property (ab)^c = a^c * b^c, we can simplify further:
(4^3)^(-5) â‹… (49)^(-5) / 7^9 â‹… 1/4^13
Simplifying the exponents:
(64)^(-5) â‹… (49)^(-5) / 7^9 â‹… 1/4^13
Now, let's solve the expression:
(64)^(-5) â‹… (49)^(-5) / 7^9 â‹… 1/4^13
Simplifying the bases raised to the negative exponents:
1/64^5 â‹… 1/49^5 / 7^9 â‹… 1/4^13
Using the properties of exponents, we can rewrite 64^5 as (2^6)^5 = 2^30, and 49^5 as (7^2)^5 = 7^10:
1/2^30 â‹… 1/7^10 / 7^9 â‹… 1/4^13
Simplifying further:
1/2^30 â‹… 1/7^(10-9) â‹… 1/4^13
= 1/2^30 â‹… 1/7^1 â‹… 1/4^13
Using the properties of exponents, we can rewrite 2^30 as (2^15)^2, and 4^13 as (2^2)^13 = 2^26:
1/(2^15)^2 â‹… 1/7^1 â‹… 1/2^26
Simplifying the exponents:
1/2^30 â‹… 1/7 â‹… 1/2^26
= 1/2^(30+26) â‹… 1/7
= 1/2^56 â‹… 1/7
Therefore, the expression (4^3 â‹… 7^(-2))^(-5) / 7^9 â‹… 4^(-13) with only positive exponents simplifies to 1/2^56 â‹… 1/7.
![Answer](/images/users/0/1/128x128.jpeg)
9 months ago
what is the answer
![Bot GPT 3.5](/images/users/4310/128x128.jpeg)
9 months ago
Apologies for the confusion. Let's simplify the expression further:
We have (4^3 â‹… 7^(-2))^(-5) / 7^9 â‹… 4^(-13)
Using the property (a^m)^n = a^(m*n), we can raise the base expressions to the power (-5):
(4^(3*(-5)) â‹… 7^(-2*(-5))) / 7^9 â‹… 4^(-13)
Simplifying exponents:
(4^(-15) â‹… 7^10) / 7^9 â‹… 4^(-13)
Applying the property a^(-n) = 1 / a^n, we can convert the negative exponents to positive exponents:
(1/4^15 â‹… 7^10) / 7^9 â‹… 1/4^13
To simplify further, we can combine the fractions and the multiplication and division:
(1 â‹… 7^10) / (4^15 â‹… 7^9 â‹… 4^13)
Canceling out common factors, we have:
7^10 / (4^15 â‹… 4^13)
Using the property of exponents a^m â‹… a^n = a^(m+n), we can combine the exponents of 4:
7^10 / 4^(15+13)
Simplifying the exponents:
7^10 / 4^28
Now, we can simplify further by looking for common factors in the numerator and denominator:
7^10 is already in its simplified form.
For 4^28, we can recognize that it can be rewritten as (2^2)^28 = 2^(2*28) = 2^56.
So, the expression simplifies to:
7^10 / 2^56
Therefore, the simplified fraction with no remaining exponents is 7^10 / 2^56.