Use the Product Rule of Exponents to simplify 510⋅55(1 point)

Responses

5^50
5 superscript 50 baseline

25^15
25 superscript 15 baseline

5^15
5 superscript 15 baseline

25^50

25 superscript 50 baseline

Use the Product Rule of Exponents to simplify 5^10⋅5^5(1 point)

Responses

5^50
5 superscript 50 baseline

25^15
25 superscript 15 baseline

5^15
5 superscript 15 baseline

25^50

5 superscript 15 baseline

What is the missing exponent in the following equation?

h^450/h^? = h^215(1 point)

The missing exponent in the equation is 235.

Simplify 12^87÷12^25.

To simplify this expression, you can use the Quotient Rule of Exponents. According to the Quotient Rule, when dividing powers with the same base, you subtract the exponents.

So, 12^87 ÷ 12^25 = 12^(87 - 25) = 12^62.

Therefore, the simplified form is 12^62.

What is the value of 6.9−2^0?(1 point)

Responses

5.9
5.9

4.9
4.9

7.9
7.9

6.9

The value of 6.9 - 2^0 is 6.9 - 1 = 5.9

Apply the Zero Power Rule to create an equivalent expression to 9⋅(−33)0+32(8−270).(2 points)

9⋅(−33)^0+3/2(8−27^0) = __ ⋅ __ +3/2( __ – __ )

Applying the Zero Power Rule, any non-zero base raised to the power of zero is equal to 1.

So, 9 ⋅ (-33)^0 + 3/2(8 − 27^0) is equivalent to 9 ⋅ 1 + 3/2(8 − 1).

Simplifying further, we have 9 + 3/2(7).

Therefore, the equivalent expression is 9 + 3/2(7).

fill in the blanks.

9 + 3/2(7) = 9 + 3/2 * 7 = 9 + (21/2) = 9 + 10.5 = 19.5

the question that I GAVE YOU. FILL IN THE BLANK. THE BLANKS ARE ___

Apologies for the misunderstanding. Here is the filled-in expression:

9 ⋅ (−33)^0 + 3/2(8 − 27^0) = 9 ⋅ 1 + 3/2(8 − 1) = 9 + 3/2(7) = 9 + 10.5 = 19.5

Solve the expression 15⋅805+4(70−6).(1 point)

15⋅8^0/5+4(7^0−6)= __

To solve the expression, we first simplify the exponential terms using the Zero Power Rule:

15⋅8^0/5 + 4(7^0−6) = 15⋅1/5 + 4(1−6)

Next, we simplify the multiplications and subtraction inside the brackets:

= 15/5 + 4(-5)
= 3 + (-20)

Finally, we add the numbers:
= 3 - 20
= -17

Therefore, the value of the expression is -17.