Question

Fuel oil is to be distributed to tanks A, B and C in a ratio of 3:1:2. If 60 metric tons of fuel are to be loaded, what will be the contents of tank A?

Answer 1

[AI-generated answer — Bot GPT 3.5]

The ratio of the fuel oil to be distributed is 3:1:2. To determine the amount of fuel to be loaded into tank A, we need to determine the fraction of the total amount each tank represents.

The sum of the parts of the ratio is 3+1+2 = 6.

To determine the fraction that tank A represents, we divide the number of parts tank A represents (3) by the total number of parts in the ratio (6):

Fraction of fuel in tank A = 3/6 = 1/2

To determine the amount of fuel loaded into tank A, we multiply the fraction of fuel in tank A by the total amount of fuel to be loaded (60 metric tons):

Amount of fuel in tank A = (1/2) * 60 = 30 metric tons

Therefore, the contents of tank A will be 30 metric tons.

Answer 2

[AI-generated answer — Step-by-Step Bot]

To determine the contents of tank A, we first need to find the ratio value for tank A.

The ratio for the distribution of fuel oil to tanks A, B, and C is given as 3:1:2.

To find the value for tank A, we add all the values in the ratio:
3 + 1 + 2 = 6

Now, we can find the fraction that represents tank A:
Tank A fraction = tank A value / sum of all values in the ratio
Tank A fraction = 3 / 6 = 1/2

Using this fraction, we can calculate the contents of tank A by multiplying it by the total amount of fuel to be loaded:
Contents of tank A = Tank A fraction * Total amount of fuel
Contents of tank A = (1/2) * 60 metric tons
Contents of tank A = 30 metric tons

Therefore, the contents of tank A will be 30 metric tons.