Identify the first quartile in the following dataset:

5, 7, 9, 4, 3, 2, 1, 0, 11, 12, 6, 3, 4, 3, 2, 6(1 point)
Responses

0
0

6.5
6.5

2.5
2.5

4

Apologies for the confusion earlier. The third quartile in the given dataset is 50.9. I apologize for the incorrect response earlier.

The range of a data set is calculated by subtracting the smallest value from the largest value. In the given data set, the smallest value is 13 and the largest value is 98.

Range = 98 - 13 = 85

Therefore, the range of the given data set is 85.

Find the interquartile range of the given dataset.

11, 13, 22, 17, 14, 21, 27, 15

(1 point)
Responses

8
8

21.5
21.5

13.5
13.5

6.5

Apologies for the confusion. The correct option for the interquartile range of the given dataset is 6.5.

Identify the third quartile in the following dataset:

53.3, 46.9, 48.1, 49.7, 52.1, 47.5, 47.2, 45.5(1 point)
Responses

50.9
50.9

53.3
53.3

47.8
47.8

47.05

so is it

50.9
50.9
or
53.3
53.3
or
47.8
47.8
or
47.05

Find the range of the given data set.

51, 13, 98, 42, 76, 28

(1 point)
Responses

98
98

23
23

13
13

85

not an option

e heights in inches of six basketball players at a local high school are given as a dataset.

70, 78, 74, 82, 68, 75

Find the range and the interquartile range of the dataset.

(1 point)
Responses

The range is 14, and the interquartile range is 8.
The range is 14, and the interquartile range is 8.

The range is 14, and the interquartile range is 4.5.
The range is 14, and the interquartile range is 4.5.

The range is 5, and the interquartile range is 8.
The range is 5, and the interquartile range is 8.

The range is 14, and the interquartile range is 74.5.

To find the range of the given dataset, we need to subtract the smallest value from the largest value. In this case, the smallest value is 68 and the largest value is 82.

Range = 82 - 68 = 14

Therefore, the range of the dataset is 14.

To find the interquartile range, we need to first find the first quartile (Q1) and the third quartile (Q3) of the dataset.

Arranging the data in ascending order: 68, 70, 74, 75, 78, 82.

Q1 is the median of the lower half of the data. Since there are 6 data points, the median will be the average of the 3rd and 4th values.

The 3rd value is 74 and the 4th value is 75.

Average of 74 and 75 = (74 + 75) / 2 = 149 / 2 = 74.5.

Q3 is the median of the upper half of the data. Since there are 6 data points, the median will be the average of the 3rd and 4th values.

The 3rd value is 78 and the 4th value is 82.

Average of 78 and 82 = (78 + 82) / 2 = 160 / 2 = 80.

The interquartile range is calculated by subtracting Q1 from Q3.

Interquartile Range = Q3 - Q1 = 80 - 74.5 = 5.5.

Therefore, the range of the dataset is 14 and the interquartile range is 5.5.

wrong

Apologies for the incorrect response earlier. Let's calculate the range and interquartile range correctly for the given dataset:

The range is calculated by subtracting the smallest value from the largest value in the dataset.
Smallest value: 68
Largest value: 82
Range = 82 - 68 = 14

Therefore, the range of the dataset is 14.

To calculate the interquartile range, we first need to find the first quartile (Q1) and the third quartile (Q3).

Arranging the data in ascending order: 68, 70, 74, 75, 78, 82.

To find Q1, we need to find the median of the lower half of the data. Since there are 6 data points, Q1 will be the average of the 2nd and 3rd values.

The 2nd value is 70 and the 3rd value is 74.
Average of 70 and 74 = (70 + 74) / 2 = 144 / 2 = 72.

To find Q3, we need to find the median of the upper half of the data. Since there are 6 data points, Q3 will be the average of the 4th and 5th values.

The 4th value is 75 and the 5th value is 78.
Average of 75 and 78 = (75 + 78) / 2 = 153 / 2 = 76.5.

The interquartile range is calculated by subtracting Q1 from Q3.
Interquartile Range = Q3 - Q1 = 76.5 - 72 = 4.5.

Therefore, the range of the dataset is 14 and the interquartile range is 4.5.

The first quartile in the given dataset is 2.5.

To find the third quartile in a dataset, we need to arrange the data in ascending order. The dataset in ascending order is:

45.5, 46.9, 47.2, 47.5, 48.1, 49.7, 52.1, 53.3

The third quartile is the median of the upper half of the data. Since there are 8 data points in the upper half, the median will be the average of the 4th and 5th values.

The 4th value is 48.1 and the 5th value is 49.7.

Average of 48.1 and 49.7 = (48.1 + 49.7) / 2 = 97.8 / 2 = 48.9

Therefore, the third quartile in the given dataset is 48.9.

To find the interquartile range of a dataset, we first need to find the first quartile (Q1) and the third quartile (Q3).

Arranging the data in ascending order: 11, 13, 14, 15, 17, 21, 22, 27.

The first quartile (Q1) is the median of the lower half of the data. Since there are 8 data points, the median will be the average of the 4th and 5th values.

The 4th value is 15 and the 5th value is 17.

Average of 15 and 17 = (15 + 17) / 2 = 32 / 2 = 16.

The third quartile (Q3) is the median of the upper half of the data. Since there are 8 data points, the median will be the average of the 4th and 5th values.

The 4th value is 21 and the 5th value is 22.

Average of 21 and 22 = (21 + 22) / 2 = 43 / 2 = 21.5.

The interquartile range is calculated by subtracting Q1 from Q3.

Interquartile Range = Q3 - Q1 = 21.5 - 16 = 5.5.

Therefore, the interquartile range of the given dataset is 5.5.