Sarah described the following situation:

When more apples grew in the backyard, the pet cat stayed indoors for a longer time.

Which of the following best describes the situation?

This is an example of correlation because there is an obvious relationship between the two scenarios.
This is an example of causation because apples cause cats to stay indoors.
This is an example of correlation because apples cause cats to stay indoors.
This is an example of causation because cats dislike apples.

This is an example of correlation because there is an obvious relationship between the two scenarios.

The following tree heights were recorded on a school campus:

61, 72, 84, 88, 77, 67, 76, 79, 63, 79, 69, 70, 86, 78, 82, 82, 80, 73, 87, 90, 73, 76, 79, 71, 75, 79, 76, 83, 84, 87, 72, 81, 89, 74, 77, 78, 81, 84

A science teacher wants to choose a data display that will highlight every height. Which display will present the information in this way?

Box plot
Circle graph
Histogram
Line plot

A line plot will present the information in a way that highlights every height.

The display summarizes grades on a World History exam.

A vertical box plot is titled world history exams, with a minimum of 54, a maximum of 94, a lower quartile of 70, a median of 83, and an upper quartile of 88.

Which of the following describes the data set?

The data is univariate and categorical.
The data is univariate and numerical.
The data is bivariate and categorical.
The data is bivariate and numerical.

The data is univariate and numerical.

The scatter plot shows the number of animal cells Clara examined in a laboratory in different months:

plot ordered pairs 1, 20 and 2, 60 and 3,100 and 4, 140 and 5, 180

What is the approximate predicted number of animal cells Clara examined in the 9th month?

280
290
340
380

Based on the given ordered pairs, we can see that the number of animal cells Clara examined is increasing at a consistent rate. The approximate rate of increase is 40 (20, 60, 100, 140).

To predict the number of animal cells Clara examined in the 9th month, we can extend the pattern of the rate of increase.

The 9th month is 4 months after the 5th month. So, we can add 4 times the rate of increase (40) to the last observed value (180).

Approximate predicted number of animal cells = 180 + (4 * 40) = 320

Therefore, the approximate predicted number of animal cells Clara examined in the 9th month is 320.

that was not one of the provided answers

Apologies for the confusion. If the answer choices provided do not include the accurate predicted number of animal cells Clara examined in the 9th month, I cannot provide a corresponding answer without further context or information. It is suggested to review the given information and options to identify a potential error or seek clarification from the source that provided the question.

The scatter plot shows the number of animal cells Clara examined in a laboratory in different months:

plot ordered pairs 1, 20 and 2, 60 and 3,100 and 4, 140 and 5, 180

What is the approximate predicted number of animal cells Clara examined in the 9th month?

280
290
340
380

answer with one of the choices given

Apologies for the confusion in my previous response. Based on the given information:

The rate of increase between each pair of months is consistent: 40 (20, 60, 100, 140).

To predict the number of animal cells Clara examined in the 9th month, we can continue this pattern.

Starting from the last observed value of 180, we can add 4 times the rate of increase (40) to estimate the 9th month.

Approximate predicted number of animal cells = 180 + (4 * 40) = 180 + 160 = 340

Therefore, the approximate predicted number of animal cells Clara examined in the 9th month is 340.

The two-way frequency table contains data about students' preferred exercise.

Enjoys swimming Enjoys cycling Row totals
Likes running 28 62 90
Does not like running 46 64 110
Column totals 74 126 200

What is the joint relative frequency of students who do not like to run and enjoy swimming?
23%
37%
46%
72%

To calculate the joint relative frequency of students who do not like to run and enjoy swimming, we need to divide the frequency of that category by the total number of students (200).

In the table, the frequency of students who do not like running and enjoy swimming is 46.

Joint relative frequency = (Frequency of the category) / (Total number of students)

Joint relative frequency = 46 / 200

Joint relative frequency = 0.23

Therefore, the joint relative frequency of students who do not like to run and enjoy swimming is 23%.

A scatter plot is made to model the number of calories in different portions of fish sticks. The data used for the scatter plot are shown in the table:

Number of portions 5 3 8 6 1 4
Number of calories 250 150 400 300 50 200

What does the slope of the model represent?
The number of calories in each portion of fish sticks
The number of fish sticks in each portion
The original number of portions of fish sticks
The price of each portion of fish sticks

The slope of the model represents the number of calories in each portion of fish sticks. As the number of portions increases, the number of calories increases at a rate determined by the slope.

An ice cream truck sells ice cream between 2 p.m. and 10 p.m. each night in the summer. At the end of the night, the driver calculates his profits and makes a graph to analyze the data. What is the average rate of change for the from the 1st hour to the 4th hour? Be sure to include the correct units of measurement.

a scatter plot with x axis labeled Hour and y axis labeled Money Earned in Dollars per Hour with points at 1 comma 54 and 2 comma 58 and 3 comma 64 and 4 comma 78 and 5 comma 96 and 6 comma 126 and 7 comma 99 and 8 comma 75

24 dollars
24 dollars per hour per hour
8 hours
8 dollars per hour per hour

To calculate the average rate of change from the 1st hour to the 4th hour, we need to find the change in money earned over that time period.

Starting from the 1st hour with a money earned value of $54 and the 4th hour with a money earned value of $78:

Change in money earned = Final value - Initial value = $78 - $54 = $24

The time period is 4 hours, as we are comparing the 1st hour to the 4th hour.

Average rate of change = Change in money earned / Time period = $24 / 4 hours = $6 per hour

Therefore, the average rate of change from the 1st hour to the 4th hour is $6 per hour.

An ice cream truck sells ice cream between 2 p.m. and 10 p.m. each night in the summer. At the end of the night, the driver calculates his profits and makes a graph to analyze the data. What is the average rate of change for the from the 1st hour to the 4th hour? Be sure to include the correct units of measurement.

a scatter plot with x axis labeled Hour and y axis labeled Money Earned in Dollars per Hour with points at 1 comma 54 and 2 comma 58 and 3 comma 64 and 4 comma 78 and 5 comma 96 and 6 comma 126 and 7 comma 99 and 8 comma 75

24 dollars
24 dollars per hour per hour
8 hours
8 dollars per hour per hour

use the answer choices provided

The average rate of change from the 1st hour to the 4th hour can be calculated by finding the change in money earned over that time period.

Starting from the 1st hour with a money earned value of $54 and the 4th hour with a money earned value of $78:

Change in money earned = Final value - Initial value = $78 - $54 = $24

The time period is 4 hours, as we are comparing the 1st hour to the 4th hour.

Average rate of change = Change in money earned / Time period = $24 / 4 hours = $6 per hour

Therefore, the average rate of change from the 1st hour to the 4th hour is $6 per hour.

None of the answer choices provided, 24 dollars, 24 dollars per hour per hour, 8 hours, or 8 dollars per hour per hour, are correct.

A food truck did a daily survey of customers to find their food preferences. The data is partially entered in the frequency table. Complete the table to analyze the data and answer the questions:

Likes hamburgers Does not like hamburgers Total
Likes burritos 49 92
Does not like burritos 75 38
Total 81 205

Part A: What percentage of the survey respondents liked neither hamburgers nor burritos? Show all work. (3 points)

Part B: What is the marginal relative frequency of all customers who like hamburgers? Show all work. (3 points)

Part C: Is there an association between liking burritos and liking hamburgers? Use ratios of joint and marginal frequencies to support your answer. (4 points)

Let's complete the missing values in the frequency table:

Likes hamburgers Does not like hamburgers Total
Likes burritos 49 ? 92
Does not like burritos 75 38 ?
Total ? 81 205

To complete the table:

Likes hamburgers Does not like hamburgers Total
Likes burritos 49 43 92
Does not like burritos 75 38 113
Total 124 81 205

Part A: To find the percentage of the survey respondents who liked neither hamburgers nor burritos, we need to find the frequency in the "Does not like hamburgers" and "Does not like burritos" category, which is 38.

Percentage = (Frequency of the category / Total frequency) * 100

Percentage = (38 / 205) * 100

Percentage = 18.54%

Therefore, 18.54% of the survey respondents liked neither hamburgers nor burritos.

Part B: To find the marginal relative frequency of all customers who like hamburgers, we need to find the frequency in the "Likes hamburgers" row, which is 124.

Marginal Relative Frequency = Frequency of the category / Total frequency

Marginal Relative Frequency = 124 / 205

Marginal Relative Frequency = 0.6049

Therefore, the marginal relative frequency of all customers who like hamburgers is approximately 0.6049.

Part C: To determine if there is an association between liking burritos and liking hamburgers, we can compare the joint relative frequency of both categories with their respective marginal relative frequencies.

Joint Relative Frequency of liking both hamburgers and burritos = 49 / 205 = 0.2390
Marginal Relative Frequency of liking hamburgers = 124 / 205 = 0.6049
Marginal Relative Frequency of liking burritos = 92 / 205 = 0.4488

If the joint relative frequency is close to the product of the marginal relative frequencies, then there is an association between the two categories.

In this case, 0.2390 is not close to the product of 0.6049 and 0.4488. Therefore, we can conclude that there is no significant association between liking burritos and liking hamburgers based on the ratios of joint and marginal frequencies.