Martin needs 3.25 gallons of red paint for his small barn and 1.25 gallons of paint for his shed. He spends $81 on paint. How much does the paint cost per gallon?
$18.00
$24.54
$27.00
$40.50
To find the cost per gallon, we need to divide the total cost by the total amount of paint used:
Total amount of paint = 3.25 + 1.25 = 4.5 gallons
Cost per gallon = $81 รท 4.5 gallons = $18.00/gallon
Therefore, the answer is $18.00.
Cooper is measuring ingredients for his special dessert. He needs a total of 70.4 mL of milk and melted butter. The recipe calls for 30.6 mL of butter. How much milk, m, does Cooper need for his recipe?
2.3 mL
39.8 mL
40.2 mL
101 mL
To find the amount of milk Cooper needs, we can subtract the amount of butter called for in the recipe from the total amount of milk and butter needed:
Milk needed = Total milk and butter needed - Butter needed
Milk needed = 70.4 mL - 30.6 mL
Milk needed = 39.8 mL
Therefore, Cooper needs 39.8 mL of milk for his recipe. The answer is 39.8 mL.
What is the value of x?
Four-fifths x minus StartFraction 1 Over 10 Endfraction = StartFraction 3 Over 10 EndFraction
One-fourth
StartFraction 8 Over 25 EndFraction
Two-fifths
One-half
First, we need to isolate the variable by adding 1/10 to both sides:
Four-fifths x - 1/10 + 1/10 = 3/10 + 1/10
Simplifying, we get:
Four-fifths x = 2/5
To isolate x, we need to divide both sides by 4/5, or multiply both sides by 5/4:
x = (2/5) * (5/4)
Simplifying, we get:
x = 1/2
Therefore, the value of x is one-half.
What is the least common denominator of the equation StartFraction 2 Over 9 EndFraction x + two-thirds x = 7?
3
9
27
63
To find the least common denominator (LCD) for the given equation, we need to find the least common multiple (LCM) of the denominators 9 and 3.
The multiples of 9 are: 9, 18, 27, 36, 45, 54, 63, ...
The multiples of 3 are: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, ...
We can see that the least common multiple of 9 and 3 is 9.
To solve the equation, we need to rewrite the fractions with the common denominator of 9:
StartFraction 2 Over 9 EndFraction x + StartFraction 2 Over 3 EndFraction x = 7
Multiplying the first fraction by 3/3, we get:
StartFraction 6 Over 27 EndFraction x
Multiplying the second fraction by 3/3, we get:
StartFraction 6 Over 9 EndFraction x
Rewriting the equation with the common denominator of 9:
StartFraction 6 Over 27 EndFraction x + StartFraction 6 Over 9 EndFraction x = 7
Combining the fractions on the left side:
StartFraction 6 Over 27 EndFraction x + StartFraction 18 Over 27 EndFraction x = 7
StartFraction 24 Over 27 EndFraction x = 7
Multiplying both sides by the reciprocal of 24/27:
x = 7 * (27/24)
Simplifying:
x = 21/8
Therefore, the LCD of the equation is 9.
A baby gains 11 pounds in its first year of life. The baby gained 4 and one-fourth pounds during the first four months and 3 and one-halfpounds in its second four months. How much did the baby gain in the last four months?
3 and one-fourthpounds
3 and one-halfpounds
4 pounds
5 pounds
The baby gained 4 and one-fourth pounds in the first 4 months and 3 and one-half pounds in the second 4 months, for a total of:
4 and 1/4 + 3 and 1/2 = 7 and 3/4 pounds gained in the first 8 months
To find how much the baby gained in the last 4 months, we can subtract this amount from the total gain in the first year:
11 - 7 and 3/4 = 3 and 1/4 pounds gained in the last 4 months
Therefore, the baby gained 3 and one-fourth pounds in the last 4 months. Answer: 3 and one-fourth pounds.
Last winter Armand had StartFraction 5 Over 6 EndFraction of a row of stacked logs. At the end of the winter he had StartFraction 8 Over 15 EndFraction of the same row left. How much wood did he burn over the winter?
1 and StartFraction 9 Over 16 EndFraction rows
1 and StartFraction 11 Over 30 EndFraction rows
StartFraction 4 Over 9 EndFraction row
StartFraction 3 Over 10 EndFraction row
Armand burned the difference between the amount of wood he had at the beginning of winter and the amount he had at the end of winter. To find this difference, we need to subtract the fraction that represents the end of winter wood from the fraction that represents the beginning of winter wood:
StartFraction 5 Over 6 EndFraction - StartFraction 8 Over 15 EndFraction = StartFraction 25 - 16 Over 30 EndFraction = StartFraction 9 Over 30 EndFraction = StartFraction 3 Over 10 EndFraction
This means that Armand burned 3/10 of the row of stacked logs over the winter.
To express this answer as a mixed number, we can divide the fraction and simplify:
3/10 = 0.3 = 3/10 = 3/10 * 10/10 = 30/100 = 15/50 = 3/10
Therefore, the amount of wood that Armand burned over the winter is 3/10 of a row, or 1 and 3/10 in mixed number form.
Answer: 1 and StartFraction 3 Over 10 EndFraction rows.
Tobin is solving the equation 3 (x minus 1.25) = 11.25. His work is shown below.
3 (x minus 1.25) = 11.25. 3 x minus 3.75 = 11.25. 3 x minus 3.75 + 3.75 = 11.25 + 3.75. 3 x = 15. 3 x times 3 = 45 times 3. x = 135.
What mistake did Tobin make?
Tobin did not distribute the 3 correctly.
Tobin should have subtracted 3.75 from each side.
Tobin should have divided by 3.
Tobin did not make a mistake.
Tobin made a mistake in the final step of his work. Instead of dividing both sides by 3 to isolate the variable x, he multiplied both sides by 3.
The correct final step would be:
x = 15/3
Simplifying:
x = 5
Therefore, the mistake Tobin made was that he should have divided by 3 in the final step, instead of multiplying by 3. Answer: Tobin should have divided by 3.
What is the value of x?
x + StartFraction 4 Over 9 EndFraction = three-fourths
StartFraction 11 Over 36 EndFraction
One-third
1 and StartFraction 11 Over 16 EndFraction
1 and StartFraction 7 Over 16 EndFraction
To isolate the variable x, we need to subtract 4/9 from both sides of the equation:
x + 4/9 - 4/9 = 3/4 - 4/9
Simplifying:
x = 27/36 - 16/36
x = 11/36
Therefore, the value of x is StartFraction 11 Over 36 EndFraction. Answer: StartFraction 11 Over 36 EndFraction.