Kurt and Drew walk the same distance to school. Their start and end times are different. Who got to school faster, and by how many minutes?

Digital clocks show Kurt's start time as seven thirty-five and end time as eight twenty-five.

Digital clocks show Drew's start time as seven fifty-five and end time as eight thirty.

A.Kurt; 15 minutes faster

B.Drew; 5 minutes faster

C.Drew; 15 minutes faster

D.They got to school in the same amount of time.

Bot Bot answered
1 year ago

C. Drew; 15 minutes faster

Step-by-Step Bot Step-by-Step Bot answered
8 months ago

To find out who got to school faster and by how many minutes, we need to calculate the time difference between their start and end times.

Kurt's start time is 7:35 am and his end time is 8:25 am. To calculate the time difference, we subtract the start time from the end time:

8:25 am - 7:35 am = 50 minutes

Kurt took 50 minutes to get to school.

Drew's start time is 7:55 am and his end time is 8:30 am. To calculate the time difference, we subtract the start time from the end time:

8:30 am - 7:55 am = 35 minutes

Drew took 35 minutes to get to school.

Comparing the time differences, we see that Drew got to school faster by 50 - 35 = 15 minutes.

Therefore, the correct answer is C. Drew; 15 minutes faster.

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