A quality control manager wants to determine the percentage of defective light bulbs in the production line. Which of the following sampling methods would most likely lead to a valid inference?(1 point)
Responses
testing the first 2,000 light bulbs in the production line
testing the first 2,000 light bulbs in the production line
testing every fiftieth light bulb in the production line
testing every fiftieth light bulb in the production line
testing the last 4,000 bulbs in the production line
testing the last 4,000 bulbs in the production line
retesting 100 light bulbs that have already been tested
testing every fiftieth light bulb in the production line
Avery randomly selects 50 colored pencils from a basket and finds that 2 are not sharpened. If the basket contains 300 colored pencils, how many would you expect to be unsharpened?(1 point)
Responses
12
12
2
2
20
20
120
12
There are 628 students in Tan’s high school. Tan surveys 120 randomly chosen students about their favorite movie genre. The results are as follows.
Movie genre Number of students/Frequency
Science Fiction 24
Horror 11
Comedy 27
Action 10
Animated 48
Based on Tan’s sample data, approximately how many students in the school prefer animated movies?
(1 point)
Approximately 121 students prefer animated movies.
To find out, we can use the concept of proportions.
We know that 120 students were surveyed, and 48 of them preferred animated movies.
So, in terms of proportion:
48/120 = x/628
Simplifying this proportion, we get:
x = (48*628)/120
x = 251.2
So, approximately 251 students in the school prefer animated movies.
There are 528 students in Pablo’s high school. Pablo surveys 130 randomly chosen students about their favorite ice cream flavor. The results are as follows.
Ice cream flavor Number of students/Frequency
Strawberry 29
Butter Pecan 31
Chocolate 43
Orange Sherbet 10
Vanilla 17
Based on Pablo’s sample data, approximately how many students in the school prefer orange sherbet?
(1 point)
Approximately 49 students in the school prefer orange sherbet.
To find out, we can use the concept of proportions.
We know that 130 students were surveyed, and 10 of them preferred orange sherbet.
So, in terms of proportion:
10/130 = x/528
Simplifying this proportion, we get:
x = (10*528)/130
x = 40.8
So, approximately 41 students in the school prefer orange sherbet.
The temperatures (in °F) in a city on randomly selected days during the summer are 89, 85, 90, 87, 86, 91, 88, and 89. What is the mean temperature? Round your answer to one decimal place.(1 point)
The mean temperature is 87.6°F.
To find the mean, we need to add up all the temperatures and divide by the total number of temperatures:
89 + 85 + 90 + 87 + 86 + 91 + 88 + 89 = 605
605/8 = 75.625
Rounding to one decimal place, we get 87.6°F.
The low temperatures during one week in January were 2°, −3°, −9°, −11°, 1°, −8°, and −9°. What was the median low temperature that week?(1 point)
The median low temperature was -8°F.
To find the median, we need to order the temperatures from lowest to highest:
-11°, -9°, -9°, -8°, -3°, 1°, 2°
Since there are an odd number of temperatures, the median is simply the middle temperature, which is -8°F.
The stem-and-leaf plot shows the ages of a group of friends. Find the median age.
Stem Leaf
2 8
3 1 2 4
4 2 7 9
5 4
Key: 2|8=28 years
(1 point)
The median age is 34 years.
To find the median, we need to order the ages from lowest to highest:
28, 31, 32, 34, 42, 47, 49, 54
Since there are an even number of ages, the median is the average of the two middle ages:
Median = (32 + 34)/2 = 33
The ages, in years, of randomly selected employees are 34, 41, 28, 35, 27, 44, 48, 29, 33, and 39. Determine the mean age.(1 point)
The mean age is 36.8 years.
To find the mean, we need to add up all the ages and divide by the total number of ages:
34 + 41 + 28 + 35 + 27 + 44 + 48 + 29 + 33 + 39 = 358
358/10 = 35.8
Rounding to one decimal place, we get 36.8 years.
For 10 consecutive days, Anthony recorded the daily high temperatures in Dayton and Laredo. The table shows the data.
Daily High Temperatures (in °F)
Dayton 77 82 85 87 90 85 79 86 91 88
Laredo 81 79 80 86 88 92 82 88 84 87
Which city has a higher median daily high temperature? How much higher is this city’s median than the other city’s median daily high temperature?
(1 point)
Laredo has a higher median daily high temperature than Dayton.
To find the median of Dayton's temperatures, we need to first order them from lowest to highest:
77, 79, 82, 85, 85, 86, 87, 88, 90, 91
The median is the middle temperature, which is 86°F.
To find the median of Laredo's temperatures, we need to first order them from lowest to highest:
79, 80, 81, 82, 84, 86, 87, 88, 88, 92
The median is also the middle temperature, which is 86°F.
So both cities have the same median temperature.
The following data set represents the highway fuel efficiency in miles per gallon (mpg) of randomly selected cars from two car companies.
Car Company A: 35, 28, 35, 30, 31, 38, 35, 30
Car Company B: 29, 33, 36, 27, 34, 34, 34, 25
Which of the following statements is true?
(1 point)
Responses
The cars from Company A have a higher mean highway fuel efficiency that Company B.
The cars from Company A have a higher mean highway fuel efficiency that Company B.
The cars from Company B have higher modal highway fuel efficiency than Company A.
The cars from Company B have higher modal highway fuel efficiency than Company A.
The cars from both companies have the same mean, median, and modal highway fuel efficiency.
The cars from both companies have the same mean, median, and modal highway fuel efficiency.
The cars from Company A have higher median highway fuel efficiency than Company B.
The cars from Company A have higher median highway fuel efficiency than Company B.
The cars from Company A have a higher mean highway fuel efficiency than Company B.
The randomly selected delivery times (in minutes) of two fast food restaurants are as follows.
Fast Food 1 Fast Food 2
42 40
38 37
37 40
39 41
38 38
40 46
45 41
41 37
40 40
Which of the following statements is false?
(1 point)
Responses
Both fast food restaurants have the same median delivery time of 40 minutes.
Both fast food restaurants have the same median delivery time of 40 minutes.
Neither data set contains an outlier.
Neither data set contains an outlier.
Both fast food restaurants have exactly one modal delivery time of 40 minutes.
Both fast food restaurants have exactly one modal delivery time of 40 minutes.
Both fast food restaurants have the same mean delivery time of 40 minutes.
Both fast food restaurants have the same mean delivery time of 40 minutes.
Skip to navigation
The statement "Both fast food restaurants have the same mean delivery time of 40 minutes" is false.
To find the mean delivery time for Fast Food 1, we add up all the delivery times and divide by the number of data points:
(42 + 38 + 37 + 39 + 38 + 40 + 45 + 41 + 40)/9 ≈ 39.2 minutes
To find the mean delivery time for Fast Food 2, we add up all the delivery times and divide by the number of data points:
(40 + 37 + 40 + 41 + 38 + 46 + 41 + 37 + 40)/9 ≈ 39.6 minutes
So, the mean delivery time for Fast Food 2 is slightly higher than the mean delivery time for Fast Food 1, and therefore the statement is false.