Write each expression using a single exponent
4^4/4^6
1/4^2 or 1/16
simplify 5^0
Any number raised to the power of 0 is always 1. Therefore, 5^0 = 1.
7^4/7^2 equal less than or more then 49
We can simplify 7^4/7^2 as:
7^4/7^2 = 7^(4-2) = 7^2
Therefore:
7^4/7^2 = 7^2 = 49
Since the equation simplifies to 49, we can say that:
7^4/7^2 = 49
And therefore, 7^4/7^2 is equal to 49.
Hi are
Hello! How may I assist you today?
Multiply the following polynomials.
2r(8r+5)
When multiplying the polynomial 2r with the expression (8r+5), we distribute the 2r to both terms inside the parentheses:
2r(8r+5) = (2r*8r) + (2r*5)
Simplifying this expression:
2r(8r+5) = 16r^2 + 10r
Therefore, the product of the polynomials 2r and (8r+5) is 16r^2 + 10r.
Multiply the following polynomials.
-2r(8r+5)
When multiplying the polynomial -2r with the expression (8r+5), we distribute the -2r to both terms inside the parentheses:
-2r(8r+5) = (-2r*8r) + (-2r*5)
Simplifying this expression:
-2r(8r+5) = -16r^2 - 10r
Therefore, the product of the polynomials -2r and (8r+5) is -16r^2 - 10r.
Multiply the following polynomials.
4a(a^2 + 7a + 4)
When multiplying 4a with the polynomial (a^2 + 7a + 4), we distribute the 4a to each term inside the parentheses:
4a(a^2 + 7a + 4) = 4a*a^2 + 4a*7a + 4a*4
Simplifying each term:
4a(a^2 + 7a + 4) = 4a^3 + 28a^2 + 16a
Therefore, the product of the polynomials 4a and (a^2 + 7a + 4) is 4a^3 + 28a^2 + 16a.
Multiply the following polynomials.
(2y – 3) (3y – 2)
We can use the FOIL method to multiply these two polynomials:
(2y - 3) (3y - 2) = 2y * 3y - 2 * 3y - 3 * 2y + 3 * 2
Simplifying each term:
(2y - 3) (3y - 2) = 6y^2 - 6y - 6y + 6
Combining like terms:
(2y - 3) (3y - 2) = 6y^2 - 12y + 6
Therefore, the product of the polynomials (2y - 3) and (3y - 2) is 6y^2 - 12y + 6.