Solve for s.
s2+12s–13=0
Write each solution as an integer, proper fraction, or improper fraction in simplest form. If there are multiple solutions, separate them with commas.
AAAaannndd the bot gets it wrong yet again!
how can you flub such easy calculation?
s = (-12 - 14) / 2 = -26/2 = -13
or, with less work,
s^2+12s–13=0
(s+13)(s-1) = 0
s = -13, 1
I apologize for the error in my previous response. You are correct that the solutions are s = -13 and s = 1. Using the formula:
s = (-b ± √(b^2 - 4ac)) / 2a
we get:
s = (-12 ± √(12^2 - 4(1)(-13))) / 2(1)
s = (-12 ± √(144 + 52)) / 2
s = (-12 ± √196) / 2
s = (-12 ± 14) / 2
which simplifies to:
s = (-12 + 14) / 2 = 1
s = (-12 - 14) / 2 = -13
Thank you for bringing this to my attention and I will make sure to double-check my calculations in the future.
To solve for s in the equation s^2 + 12s - 13 = 0, we can use the quadratic formula. The quadratic formula states that for any quadratic equation in the form ax^2 + bx + c = 0, the solutions for x are given by:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this case, the equation is s^2 + 12s - 13 = 0, where a = 1, b = 12, and c = -13.
Substituting the values into the quadratic formula, we have:
s = (-12 ± √(12^2 - 4(1)(-13))) / (2(1))
Simplifying further:
s = (-12 ± √(144 + 52)) / 2
s = (-12 ± √196) / 2
s = (-12 ± 14) / 2
Now, we can solve for s by considering two cases:
Case 1:
s = (-12 + 14) / 2 = 2 / 2 = 1
Case 2:
s = (-12 - 14) / 2 = -26 / 2 = -13
Therefore, the solutions for s in the equation s^2 + 12s - 13 = 0 are 1 and -13.
Using the quadratic formula:
s = (-b ± √(b^2 - 4ac)) / 2a
In this case, a = 1, b = 12, and c = -13. Plugging in:
s = (-12 ± √(12^2 - 4(1)(-13))) / 2(1)
s = (-12 ± √(144 + 52)) / 2
s = (-12 ± √196) / 2
s = (-12 ± 14) / 2
So the solutions are:
s = (-12 + 14) / 2 = 1
s = (-12 - 14) / 2 = -13/2
Therefore, the solutions are:
s = 1, -13/2