A single, standard number cube is tossed. what is the probability of getting a number greater than 3? HELP
There are 6 possible outcomes when a number cube is tossed: 1, 2, 3, 4, 5, or 6.
Out of those outcomes, there are 3 that are greater than 3: 4, 5, and 6.
So the probability of getting a number greater than 3 is 3/6 or 1/2, which can also be written as 50%.
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a game involves spinning this spinner. what is the probability of the pointer landing on R?
I'm sorry, but I cannot answer your question without seeing the spinner or its image. Please provide a description or an image of the spinner for me to calculate the probability of the pointer landing on R.
a game involves spinning this spinner. what is the probability of the pointer landing on R? the image shows 4 R's 2 B's 1 G and 1 Y, the possible answers are 1/4, 1/2 ,1/8 and 3/8
There are a total of 4 + 2 + 1 + 1 = 8 equally likely possible outcomes when the spinner is spun.
The probability of landing on R is the number of ways that the spinner can land on R divided by the total number of possible outcomes. There are 4 ways that the spinner can land on R, so the probability of landing on R is:
number of ways to land on R / total number of possible outcomes = 4/8 = 1/2
Therefore, the probability of the pointer landing on R is 1/2, which is the second answer choice.
The table shows the color preferences of 50 shoppers at the mall. what is the probability that one shopper, selected at random from the 50 surveyed, preferred the color red or blue?
7 red, 3 yellow, 13 blue ,15 green and 12 orange. possible answers are 7/50, 2/5, 1/2 15/30.
The total number of shoppers surveyed is 50. Out of these shoppers, the number of shoppers who preferred red or blue is 7 + 13 = 20.
So the probability that a shopper selected at random from the 50 surveyed preferred the color red or blue is:
number of shoppers who preferred red or blue / total number of shoppers surveyed = 20/50 = 2/5
Therefore, the probability that one shopper, selected at random from the 50 surveyed, preferred the color red or blue is 2/5, which is the second answer choice.
A standard number cube with the numbers 1 through 6 is rolled. find the probability of rolling a number greater than 4. possible answers 1/6, 1/3, 5/6, 2/3.
When rolling a standard number cube, there are 6 possible outcomes: 1, 2, 3, 4, 5, or 6.
Out of these outcomes, only 2 are greater than 4, which are 5 and 6.
So the probability of rolling a number greater than 4 is:
number of outcomes that are greater than 4 / total number of possible outcomes = 2/6 = 1/3
Therefore, the probability of rolling a number greater than 4 is 1/3, which is the second answer choice.
jamie is playing a game in which she rolls a number cube 20 times. the results are recorded in the chart below. what is the experimental probability of rolling a one or two? number on cube
1, 2, 3, 4, 5, 6. Number of times event occurs, 4, 2, 8, 3, 0.
According to the chart, Jamie rolled a 1 or a 2 a total of 4 + 2 = 6 times out of the 20 rolls.
So the experimental probability of rolling a one or two is:
number of times rolling a one or two / total number of rolls = 6/20 = 3/10
Therefore, the experimental probability of rolling a one or two is 3/10.
jamie is playing a game in which she rolls a number cube 20 times. the results are recorded in the chart below. what is the experimental probability of rolling a one or two? number on cube
1, 2, 3, 4, 5, 6. Number of times event occurs, 4, 2, 8, 3, 0. possible answers 0.30, 0.60, 0.40, 0.75.
According to the chart, Jamie rolled a 1 or a 2 a total of 4 + 2 = 6 times out of the 20 rolls.
So the experimental probability of rolling a one or two is:
number of times rolling a one or two / total number of rolls = 6/20 = 3/10
Therefore, the experimental probability of rolling a one or two is 0.30, which is the first answer choice.
From a barrel of colored marbles, you randomly select 5 blue, 2 yellow, 3 red, 4 green, and 2 purple marbles. find the experimental probability of randomly selecting a marble that is NOT yellow.
The total number of marbles in the barrel is:
5 blue + 2 yellow + 3 red + 4 green + 2 purple = 16 marbles
The number of marbles that are not yellow is:
16 - 2 (yellow marbles) = 14 marbles
So the experimental probability of randomly selecting a marble that is not yellow is:
number of marbles that are not yellow / total number of marbles = 14/16 = 7/8
Therefore, the experimental probability of randomly selecting a marble that is not yellow is 7/8.
the probability of winning a game is 25% how many times should you expect to win if you play 36 times?
If the probability of winning a game is 25%, the probability of losing the game is 100% - 25% = 75%.
The number of times we can expect to win when playing the game 36 times is equal to the total number of trials (36) multiplied by the probability of winning the game (25%) or:
Expected number of wins = 36 x 0.25 = 9
Therefore, you can expect to win the game 9 times if you play it 36 times.
a survey showed that 25% of students chose cola as their favorite soda; 40% chose orange; and the other 35% chose grape. if you survey 32 students from the same group, how many will chose cola?
If 25% of the students chose cola as their favorite soda, then the proportion of students who chose cola is:
25% = 0.25
To find out how many students will choose cola if we survey 32 students, we can multiply the proportion of students who chose cola by the total number of students surveyed:
Number of students who chose cola = 0.25 x 32 = 8
Therefore, we can expect 8 students to choose cola if we survey 32 students.
Mary works in a factory that produces 1000 telephones each day. when 30 telephones were sampled, it was found that 9 were defective. estimate how many telephones are defective each day.
To estimate the number of defective telephones each day, we can use proportions.
If 9 out of 30 telephones are defective, then the proportion of defective telephones in the sample is:
9/30 = 0.30
We can use this proportion to estimate the number of defective telephones in the whole production of 1000 telephones as follows:
Number of defective telephones = Proportion of defective telephones x Total number of telephones produced
Number of defective telephones = 0.30 x 1000 = 300
Therefore, we can estimate that 300 telephones are defective each day.
the spinner is divided into equal parts. use a tree diagram to find the probability that the spinner will land on a consonant both times if the spinner is spun twice, image shows 1 N, 1 E and 1 U on the spinner.
It's not possible to draw a tree diagram here, but we can solve this using multiplication rule of probability.
The spinner has 3 equal parts; one each for N (a consonant), E and U (both vowels).
So the probability of landing on a consonant on the first spin is 1/3. Since we are spinning the spinner twice, the probability of landing on a consonant on the second spin is also 1/3.
According to the multiplication rule of probability, the joint probability (probability of both events happening) is the product of the individual probabilities.
So the probability of landing on a consonant both times is:
P(consonant first AND consonant second) = P(consonant first) x P(consonant second) = 1/3 x 1/3 = 1/9
Therefore, the probability of the spinner landing on a consonant both times is 1/9.
an ice cream shop offers 5 different flavors of ice cream and 9 different toppings. how many choices are possible for a single serving of ice cream with one topping?
To find the number of possible choices for a single serving of ice cream with one topping, we can use the multiplication rule of counting.
There are 5 different flavors of ice cream and 9 different toppings.
For each flavor of ice cream, there are 9 possible choices of toppings.
Therefore, the total number of possible choices is:
Number of possible choices = number of choices of ice cream x number of choices of toppings
Number of possible choices = 5 x 9 = 45
Therefore, there are 45 choices possible for a single serving of ice cream with one topping.
suzy likes to mix and match her 3 necklaces 2 bracelets and 6 hats the colors are listed in the table. on monday she randomly picks a bracelet a necklace and a hat. what is the probability of suzy choosing a red bracelet and silver hat? table necklace has red green and gold. bracelet has red and black. hat has silver yellow green gold black and white.
The probability of Suzy choosing a red bracelet and silver hat can be calculated as the product of the probability of each event happening.
The probability of Suzy choosing a red bracelet is 1/2 (given that there are two options: red and black).
The probability of Suzy choosing a silver hat is 1/6 (given that there are six options: silver, yellow, green, gold, black, and white).
Since there are no restrictions on the choice of necklace, we can assume an equal probability of choosing a necklace of any color. Therefore, the probability of Suzy choosing any necklace is 1/3.
So the probability of Suzy choosing a red bracelet and silver hat is the product of these probabilities:
Probability of red bracelet and silver hat = probability of red bracelet x probability of silver hat x probability of any necklace
Probability of red bracelet and silver hat = 1/2 x 1/6 x 1/3 = 1/36
Therefore, the probability of Suzy choosing a red bracelet and silver hat is 1/36.
suzy likes to mix and match her 3 necklaces 2 bracelets and 6 hats the colors are listed in the table. on monday she randomly picks a bracelet a necklace and a hat. what is the probability of suzy choosing a red bracelet and silver hat? table necklace has red green and gold. bracelet has red and black. hat has silver yellow green gold black and white. possible answers 1/2 1/4 1/6 1/12.
The probability of Suzy choosing a red bracelet and silver hat can be calculated as the product of the probability of each event happening.
The probability of Suzy choosing a red bracelet is 1/2 (given that there are two options: red and black).
The probability of Suzy choosing a silver hat is 1/6 (given that there are six options: silver, yellow, green, gold, black, and white).
Since there are no restrictions on the choice of necklace, we can assume an equal probability of choosing a necklace of any color. Therefore, the probability of Suzy choosing any necklace is 1/3.
So the probability of Suzy choosing a red bracelet and silver hat is the product of these probabilities:
Probability of red bracelet and silver hat = probability of red bracelet x probability of silver hat x probability of any necklace
Probability of red bracelet and silver hat = 1/2 x 1/6 x 1/3 = 1/36
Therefore, the probability of Suzy choosing a red bracelet and silver hat is 1/36, which is closest in value to the fourth answer choice, 1/12.
Which events are dependent? possible answers: you toss three coins and get one head and one tail. you choose three different toppings for a sundae. you draw two colored pencils without replacing them and get one red and one yellow pencil. you pull a yellow marble from a bag of marbles return it and then pull a green marble.
The dependent events are those events where the outcome of one event affects the probability of the outcome of the other event.
Out of the given options, the event that represents dependent events is:
- You pull a yellow marble from a bag of marbles, return it and then pull a green marble.
In this case, the probability of pulling a green marble in the second draw depends on the outcome of the first draw, i.e., whether a yellow marble was selected in the first draw or not. If a yellow marble was selected and returned to the bag, the probability of selecting a green marble changes compared to the situation where a yellow marble was not selected.
The other options - tossing three coins and getting one head and one tail, choosing three different toppings for a sundae, and drawing two colored pencils without replacing them and getting one red and one yellow pencil - represent independent events since the outcome of one event does not affect the probability of the outcome of the other event.
If two coins are tossed what is the probability that first coin will show heads and the second coin show tails?
When two coins are tossed, there are four possible outcomes: HH, HT, TH, and TT. Here H represents heads and T represents tails.
Out of these four possible outcomes, only one outcome - HT - has the first coin showing heads and the second coin showing tails.
So the probability of the first coin showing heads and the second coin showing tails is:
Number of outcomes with the first coin showing heads and the second coin showing tails / Total number of possible outcomes
Probability = 1/4
Therefore, the probability that the first coin will show heads and the second coin will show tails in two coin tosses is 1/4.
you are making your own pizza, you have 3 types of sauces 3 types of cheese and 2 different toppings if you choose only one of each type of ingredient how many different pizzas can you make?
To find the total number of different pizzas that can be made with the given choices of sauce, cheese, and toppings, we can use the multiplication rule of counting.
There are 3 types of sauces, 3 types of cheese, and 2 different toppings.
To make a pizza, we need to choose one type of sauce, one type of cheese, and one topping.
By the multiplication rule, the total number of different pizzas that can be made is:
Number of different pizzas = Number of choices of sauce x Number of choices of cheese x Number of choices of topping
Number of different pizzas = 3 x 3 x 2 = 18
Therefore, we can make 18 different pizzas with the given choices of sauce, cheese, and toppings if we choose only one of each type of ingredient.