Fatoumata has a bag that contains orange chews, apple chews, and watermelon chews. She performs an experiment. Fatoumata randomly removes a chew from the bag, records the result, and returns the chew to the bag. Fatoumata performs the experiment 29 times. The results are shown below:
A orange chew was selected 6 times.
A apple chew was selected 10 times.
A watermelon chew was selected 13 times.
Based on these results, express the probability that the next chew Fatoumata removes from the bag will be orange or apple as a percent to the nearest whole number.
The probability of selecting an orange chew on the next trial is 6/29, and the probability of selecting an apple chew is 10/29. So, the probability of selecting an orange or apple chew is:
6/29 + 10/29 = 16/29
Converting this fraction to a percent, we get:
(16/29) x 100% ≈ 55%
Therefore, the probability of selecting an orange or apple chew as a percent to the nearest whole number is 55%.
A spinner is divided into five colored sections that are not of equal size: red, blue, green, yellow, and purple. The spinner is spun several times, and the results are recorded below:
Color: Red
Frequency: 20
Color: Blue
Frequency: 9
Color: Green
Frequency: 11
Color: Yellow
Frequency: 7
Color: Purple
Frequency: 16
Based on these results, express the probability that the next spin will land on red or green or purple as a decimal to the nearest hundredth.
The total number of spins recorded is:
20 + 9 + 11 + 7 + 16 = 63
The probability of landing on red is:
20/63
The probability of landing on green is:
11/63
The probability of landing on purple is:
16/63
To find the probability of landing on red or green or purple, we add their probabilities:
20/63 + 11/63 + 16/63 = 47/63
Converting this fraction to a decimal to the nearest hundredth, we get:
47/63 ≈ 0.75
Therefore, the probability of landing on red or green or purple as a decimal to the nearest hundredth is 0.75.
There is a spinner with 14 equal areas, numbered 1 through 14. If the spinner is spun one time, what is the probability that the result is a multiple of 4 and a multiple of 3?
The multiples of 4 and 3 are 12. There is only 1 slice which contains 12 out of the 14 possible numbers. Therefore, the probability of the spinner landing on a number that is a multiple of both 4 and 3 is:
1/14
Therefore, the probability that the result is a multiple of 4 and a multiple of 3 after spinning the spinner one time is 1/14.
There is a spinner with 8 equal areas, numbered 1 through 8. If the spinner is spun one time, what is the probability that the result is a multiple of 2 and a multiple of 3?
The multiples of 2 and 3 are 6. There is 1 slice containing 6 in the spinner. Therefore, the probability of the spinner landing on a number that is a multiple of both 2 and 3 is:
1/8
Therefore, the probability that the result is a multiple of 2 and a multiple of 3 after spinning the spinner one time is 1/8.
A bag contains 5 red marbles, 3 blue marbles and 6 green marbles. If two marbles are drawn out of the bag, what is the exact probability that both marbles drawn will be red?
The probability of drawing a red marble on the first draw is 5/14, since there are 5 red marbles out of 14 total marbles. The probability of drawing another red marble on the second draw is 4/13, since there will be one less marble in the bag and one less red marble.
To find the probability that both marbles are red, we multiply their probabilities:
(5/14) × (4/13) = 20/182 = 10/91
Therefore, the exact probability that both marbles drawn will be red is 10/91.
A bag contains 8 red marbles, 7 blue marbles and 2 green marbles. If two marbles are drawn out of the bag, what is the exact probability that both marbles drawn will be green?
The probability of drawing a green marble on the first draw is 2/17, since there are 2 green marbles out of 17 total marbles. After one green marble is drawn, there will be 16 marbles left in the bag, including one green marble. So the probability of drawing another green marble on the second draw is 1/16.
To find the probability that both marbles are green, we multiply their probabilities:
(2/17) × (1/16) = 2/272 = 1/136
Therefore, the exact probability that both marbles drawn will be green is 1/136.
A bag contains 3 red marbles, 7 blue marbles and 8 green marbles. If three marbles are drawn out of the bag, what is the exact probability that all three marbles drawn will be green?
The probability of drawing a green marble on the first draw is 8/18, since there are 8 green marbles out of 18 total marbles. After one green marble is drawn, there will be 17 marbles left in the bag, including 7 green marbles. So the probability of drawing another green marble on the second draw is 7/17. After two green marbles are drawn, there will be 16 marbles left in the bag, including 6 green marbles. So the probability of drawing another green marble on the third draw is 6/16.
To find the probability that all three marbles are green, we multiply their probabilities:
(8/18) × (7/17) × (6/16) = 168/4896 = 7/204
Therefore, the exact probability that all three marbles drawn will be green is 7/204.
A bag contains 5 red marbles, 6 blue marbles and 3 green marbles. If three marbles are drawn out of the bag, what is the exact probability that all three marbles drawn will be red?
The probability of drawing a red marble on the first draw is 5/14, since there are 5 red marbles out of 14 total marbles. After one red marble is drawn, there will be 13 marbles left in the bag, including 4 red marbles. So the probability of drawing another red marble on the second draw is 4/13. After two red marbles are drawn, there will be 12 marbles left in the bag, including 3 red marbles. So the probability of drawing another red marble on the third draw is 3/12.
To find the probability that all three marbles are red, we multiply their probabilities:
(5/14) × (4/13) × (3/12) = 3/364
Therefore, the exact probability that all three marbles drawn will be red is 3/364.
Joseph is playing Apex Legends. In a normal Apex Pack, there is a 1 out of 500 chance of receiving Heirloom Shards. So far, Joseph has opened 379 Apex Packs. How long until he receives Heirloom Shards?
The probability of NOT getting Heirloom Shards in a single Apex Pack is:
1 - 1/500 = 499/500
The probability of NOT getting Heirloom Shards in 379 Apex Packs is:
(499/500)^379 ≈ 0.192
So the probability of getting Heirloom Shards in 379 Apex Packs is approximately:
1 - 0.192 = 0.808
This means that there is an 80.8% chance that Joseph has not yet received Heirloom Shards after opening 379 Apex Packs.
To find the expected number of Apex Packs Joseph needs to open to have a 50% chance of receiving Heirloom Shards, we can use the formula:
- ln(0.5) / ln(1 - 1/500) ≈ 693.147
Therefore, Joseph is expected to open approximately 693 Apex Packs before he has a 50% chance of receiving Heirloom Shards.
A bag contains 3 red marbles, 5 blue marbles and 4 green marbles. If three marbles are drawn out of the bag, what is the exact probability that all three marbles drawn will be blue?
The probability of drawing a blue marble on the first draw is 5/12, since there are 5 blue marbles out of 12 total marbles. After one blue marble is drawn, there will be 11 marbles left in the bag, including 4 blue marbles. So the probability of drawing another blue marble on the second draw is 4/11. After two blue marbles are drawn, there will be 10 marbles left in the bag, including 3 blue marbles. So the probability of drawing another blue marble on the third draw is 3/10.
To find the probability that all three marbles are blue, we multiply their probabilities:
(5/12) × (4/11) × (3/10) = 3/44
Therefore, the exact probability that all three marbles drawn will be blue is 3/44.
A bag contains 3 red marbles, 7 blue marbles and 5 green marbles. If three marbles are drawn out of the bag, what is the EXACT probability that all three marbles drawn will be green?
The probability of drawing a green marble on the first draw is 5/15, since there are 5 green marbles out of 15 total marbles. After one green marble is drawn, there will be 14 marbles left in the bag, including 4 green marbles. So the probability of drawing another green marble on the second draw is 4/14. After two green marbles are drawn, there will be 13 marbles left in the bag, including 3 green marbles. So the probability of drawing another green marble on the third draw is 3/13.
To find the probability that all three marbles are green, we multiply their probabilities:
(5/15) × (4/14) × (3/13) = 1/91
Therefore, the exact probability that all three marbles drawn will be green is 1/91.
A bag contains 7 red marbles, 8 blue marbles and 3 green marbles. If three marbles are drawn out of the bag, what is the exact probability that all three marbles drawn will be blue?
The probability of drawing a blue marble on the first draw is 8/18, since there are 8 blue marbles out of 18 total marbles. After one blue marble is drawn, there will be 17 marbles left in the bag, including 7 blue marbles. So the probability of drawing another blue marble on the second draw is 7/17. After two blue marbles are drawn, there will be 16 marbles left in the bag, including 6 blue marbles. So the probability of drawing another blue marble on the third draw is 6/16.
To find the probability that all three marbles are blue, we multiply their probabilities:
(8/18) × (7/17) × (6/16) = 168/4896 = 7/204
Therefore, the exact probability that all three marbles drawn will be blue is 7/204.
How to beat Kokushibo
Kokushibo is a powerful demon from the anime/manga series Demon Slayer: Kimetsu no Yaiba. He is portrayed as a formidable opponent with many unique abilities and powers, making him a difficult opponent to defeat. Here are some tips that may help in defeating Kokushibo:
1. Use the Sun Breathing technique: In the series, sunlight is shown to be an extremely powerful weapon against demons. If the demon is exposed to sunlight, they can be weakened significantly. The Sun Breathing technique is a powerful technique used by the protagonists of the series, and it may be effective in weakening Kokushibo.
2. Attack with swords: Kokushibo wields a powerful sword that is capable of cutting through almost anything. If the hero can also wield a sword, it may provide a means to go face to face with him. However, it should be noted that Kokushibo is an experienced swordsman and will not be easy to defeat.
3. Use surprise and teamwork: In the series, some of the most powerful demons were defeated through use of surprise, distraction, or teamwork. An example of this is when multiple characters attack at once, simultaneously from different sides. This can exploit the demon's limited field of view and confusion to land a crucial blow.
4. Attack during the day: In the series, the demons are shown to be much weaker during the day than they are at night. Therefore, if an opportunity arises, it may be helpful to try and face Kokushibo during daylight hours.
5. Focus on his weaknesses: Every demon has their own unique weaknesses, and it is important to identify and exploit these accordingly. In the series, Kokushibo's weaknesses are not explicitly shown, but it may be helpful to watch for patterns in his behavior and fighting style to determine where his vulnerabilities lie.
Overall, defeating Kokushibo will not be easy. It will likely require a combination of multiple techniques, cooperation, and strategic planning.
For Emily's lemonade recipe, 9 lemons are required to make 15 cups of lemonade. Fill out a table of equivalent ratios and plot the points on the coordinate axes provided.
Table of equivalent ratios:
| Cups of Lemonade | Lemons |
|---|---|
| 3 | 1.8 |
| 6 | 3.6 |
| 9 | 5.4 |
| 12 | 7.2 |
| 15 | 9 |
Plotting the points on the coordinate axes:
```
| *
9 | *
|
6 | *
|
3 | *
--------
3 6 9 12 15 (Cups of Lemonade)
```
Note: The points on the graph may not be exactly precise due to rounding.
An aquarium can be modeled as a right rectangular prism. Its dimensions are 19 in by 15 in by 12 in. How many cubic inches of water are in it when it is full? Round your answer to the nearest tenth if necessary.
The volume of a right rectangular prism is given by the formula V = lwh, where l, w, and h represent the length, width, and height of the prism, respectively.
Substituting the given values, we get:
V = (19 in)(15 in)(12 in)
V = 3,420 cubic inches
Therefore, when the aquarium is full, it can hold 3,420 cubic inches of water.
The volume of a tree stump can be modeled by considering it as a right cylinder. Ashley measures its height as 1.2 ft and its radius as 20 in. Find the volume of the stump in cubic inches. Round your answer to the nearest tenth if necessary.
First, we need to convert the height to inches so that all the units match. Since there are 12 inches in a foot, we have:
1.2 ft × 12 in/ft = 14.4 in
Now we can use the formula for the volume of a cylinder, V = πr^2h, where r is the radius and h is the height. However, the radius given is in inches and we want the answer in cubic inches, so we have to ensure our units are consistent. Remember that 1 ft = 12 in, so we have:
r = 20 in
h = 14.4 in
Plugging these values into the formula, we get:
V = π(20 in)^2(14.4 in)
V ≈ 18,130.9 cubic inches
Therefore, the volume of the tree stump is approximately 18,130.9 cubic inches.