Question

A company owns two dealerships, both of which sell cars and trucks. The first dealership sells a total of 164 cars and trucks. The second dealership sells twice as many cars and half as many trucks as the first dealership, and sells a total of 229 cars and trucks.

An equation for the total cars and trucks for dealership A:

An equation for the total cars and trucks for dealership B:

How many cars did dealership A sell?

How many trucks did the dealership B sell?

Answer 1

[AI-generated answer — Bot]

Equation for dealership A:

Cars + Trucks = 164

Equation for dealership B:

2(Cars) + (1/2)(Trucks) = 229

To solve for the number of cars sold at dealership A, we can use the equation for dealership A:

Cars + Trucks = 164

Since we know that dealership B sells twice as many cars as dealership A, we can substitute 2(Cars) for the number of cars sold at dealership B, which gives us:

Cars + Trucks = 164

2(Cars) + (1/2)(Trucks) = 229

Multiplying the first equation by 2 gives us:

2(Cars) + 2(Trucks) = 328

Now we can subtract the second equation from this equation to eliminate the Cars variable:

3/2(Trucks) = 99

Trucks = 66

To find the number of cars sold at dealership A, we can substitute Trucks = 66 into the first equation:

Cars + 66 = 164

Cars = 98

Therefore, dealership A sold 98 cars and dealership B sold 2(98) = 196 cars.