helppp The points scored by a football team are 17, 23, 15, 21, 7, and 13. What is the range?(1 point)
The range is 16.
To find the range, you need to subtract the lowest value (which is 7) from the highest value (which is 23).
23 - 7 = 16
The range of Student 1's math quiz scores is:
92 - 75 = 17
The range of Student 2's math quiz scores is:
93 - 72 = 21
Based on the range, Student 1 performed more consistently on their math quizzes as their range is smaller than that of Student 2.
The graph shows the number of members of the Math Club from the years 2015 to 2021. Find the range.
(1 point)
Without the graph, we cannot provide the range. Please provide the graph or the data represented in the graph.
A poll is conducted to determine who is most likely to win the election for town mayor. Two random samples of 500 residents each are polled. The data is as follows.
Candidate A Candidate B Total
Sample 1 346 154 500
Sample 2 248 252 500
What percentage of the total polled residents would vote for Candidate A as the town mayor?
The total number of residents polled is 1000 (500 in Sample 1 + 500 in Sample 2).
The total number of residents who would vote for Candidate A is 346 + 248 = 594.
To find the percentage, we can use the following formula:
percentage = (part/whole) x 100%
In this case, the part (number of residents who would vote for Candidate A) is 594 and the whole (total number of residents polled) is 1000.
So,
percentage = (594/1000) x 100%
= 59.4%
Therefore, 59.4% of the total polled residents would vote for Candidate A as the town mayor.
To determine the average height of trees in a national forest, 10 trees are randomly selected. Their heights in feet are 85.4, 87.6, 87.1, 85.6, 85.9, 85.3, 84.9, 83.7, 84.0, and 85.2. To ensure the accuracy of the data, another set of 10 trees is randomly selected. Their heights are 87.1, 88.0, 84.2, 85.3, 86.5, 84.2, 83.2, 84.1, 85.2, and 87.3. What is the difference between the mean heights of the trees of these two random samples?(1 point)
Here are the math quiz scores for Student 1 and Student 2.
Student 1: 75 80 84 79 92 86 88 86 86 90
Student 2: 83 85 91 93 72 85 76 80 82 89
Find the range of each student’s math quiz scores. Based on the range, which student performed more consistently on their math quizzes?
(2 points)
The range of Student 1’s math quiz scores is
. The range of Student 2’s math quiz scores is
. Based on the range, Student
performed more consistently on the math quizzes.
The numbers of miles Ron biked are 31, 35, 49, 32, 45, 29, 33, 28, and 40.
Determine the range of this data set.(1 point)
To find the range, we need to subtract the smallest value from the largest value in the data set.
The smallest value is 28 and the largest value is 49.
So,
Range = Largest value - Smallest value = 49 - 28 = 21
Therefore, the range of the given data set is 21.
Which of the following data sets has the smallest range?(1 point)
Responses
{50, 30, 10, 0, 80, 100}
left brace 50, 30, 10, 0, 80, 100 right brace
{37, 19, 40, 54, 75, 68}
left brace 37, 19, 40, 54, 75, 68 right brace
{324, 318, 367, 312, 389, 337}
left brace 324, 318, 367, 312, 389, 337 right brace
{148, 145, 117, 148, 199, 172}
The data set {50, 30, 10, 0, 80, 100} has the smallest range.
To find the range of each data set:
For {50, 30, 10, 0, 80, 100}, the range is 100 - 0 = 100.
For {37, 19, 40, 54, 75, 68}, the range is 75 - 19 = 56.
For {324, 318, 367, 312, 389, 337}, the range is 389 - 312 = 77.
For {148, 145, 117, 148, 199, 172}, the range is 199 - 117 = 82.
Therefore, the data set {50, 30, 10, 0, 80, 100} has the smallest range of 100 - 0 = 100.
Measures of Variation Quick Check
3 of 53 of 5 Items
Question
The data from two random samples of 200 people regarding their favorite nuts is shown in the following table.
Almond Pistachio Cashew Walnuts Total
Sample 1 40 62 63 35 200
Sample 2 43 64 61 32 200
Based on the two samples, what percentage of the people prefer cashew nuts?
(1 point)
Responses
31%
31%
30.5%
30.5%
62%
62%
31.5%
31.5%
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The total number of people polled is 400 (200 in Sample 1 + 200 in Sample 2).
The total number of people who prefer cashew nuts is 63 + 61 = 124.
To find the percentage, we can use the following formula:
percentage = (part/whole) x 100%
In this case, the part (number of people who prefer cashew nuts) is 124 and the whole (total number of people polled) is 400.
So,
percentage = (124/400) x 100%
= 31%
Therefore, 31% of the people prefer cashew nuts based on the two random samples.
The following data sets represent the highway fuel efficiency in miles per gallon (mpg) of randomly selected cars from two car companies. Which company has cars that are more consistent in highway fuel efficiency?
Car Company A: 35, 28, 35, 30, 31, 36, 35, 30
Car Company B: 29, 33, 40, 27, 34, 34, 34, 25
(1 point)
Responses
Car Company A is more consistent, because the range of highway fuel efficiency of its cars is higher than that of Car Company B.
Car Company A is more consistent, because the range of highway fuel efficiency of its cars is higher than that of Car Company B.
Car Company A is more consistent, because the range of highway fuel efficiency of its cars is lower than that of Car Company B.
Car Company A is more consistent, because the range of highway fuel efficiency of its cars is lower than that of Car Company B.
Cars from both companies have equally consistent highway fuel efficiency.
Cars from both companies have equally consistent highway fuel efficiency.
Car Company B is more consistent, because the range of highway fuel efficiency of its cars is lower than that of Car Company A.
Car Company B is more consistent, because the range of highway fuel efficiency of its cars is lower than that of Car Company A.
The range of Car Company A's highway fuel efficiency is:
36 - 28 = 8
The range of Car Company B's highway fuel efficiency is:
40 - 25 = 15
Since the range of Car Company B's highway fuel efficiency is higher than Car Company A's, it means that Car Company B's cars are more consistent in highway fuel efficiency. Therefore, the correct answer choice is:
Car Company B is more consistent, because the range of highway fuel efficiency of its cars is lower than that of Car Company A.
Measures of Variation Quick Check
5 of 55 of 5 Items
Question
The randomly selected delivery times, in minutes, of two restaurants are as follows. Which restaurant has more consistent delivery times?
Restaurant 1 Restaurant 2
40 42
37 38
40 37
41 39
38 38
46 40
41 42
37 41
40 40(1 point)
Responses
Restaurant 2 is more consistent, because the range of its delivery times is higher than that of Restaurant 1.
Restaurant 2 is more consistent, because the range of its delivery times is higher than that of Restaurant 1.
The delivery times of both restaurants are equally consistent.
The delivery times of both restaurants are equally consistent.
Restaurant 1 is more consistent, because the range of its delivery times is lower than that of Restaurant 2.
Restaurant 1 is more consistent, because the range of its delivery times is lower than that of Restaurant 2.
Restaurant 2 is more consistent, because the range of its delivery times is lower than that of Restaurant 1.
Restaurant 2 is more consistent, because the range of its delivery times is lower than that of Restaurant 1.
To determine which restaurant has more consistent delivery times, we need to find the range of delivery times for both restaurants.
The range of delivery times for Restaurant 1 is:
46 - 37 = 9
The range of delivery times for Restaurant 2 is:
42 - 37 = 5
Since the range of delivery times for Restaurant 2 is lower than that of Restaurant 1, it means that Restaurant 2 has more consistent delivery times. Therefore, the correct answer is:
Restaurant 2 is more consistent, because the range of its delivery times is lower than that of Restaurant 1.
We can first find the mean height of the first set of 10 trees:
(85.4 + 87.6 + 87.1 + 85.6 + 85.9 + 85.3 + 84.9 + 83.7 + 84.0 + 85.2) / 10
= 85.67
So the mean height of the first set of 10 trees is 85.67 feet.
Similarly, we can find the mean height of the second set of 10 trees:
(87.1 + 88.0 + 84.2 + 85.3 + 86.5 + 84.2 + 83.2 + 84.1 + 85.2 + 87.3) / 10
= 85.92
So the mean height of the second set of 10 trees is 85.92 feet.
The difference between the mean heights of the two random samples is:
85.92 - 85.67 = 0.25
Therefore, the difference between the mean heights of the two random samples is 0.25 feet.