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2y-6 = 6y-18
y=3, so x = 0
-x+2y=6
6y=x+18
y=3, so x = 0
Let's use the first equation:
-x + 2y = 6
Substituting y = 3:
-x + 2(3) = 6
Simplifying:
-x + 6 = 6
-x = 0
x = 0
Therefore, the solution to the system of equations is (0, 3) and the x-value of the solution is 0.