A tennis player hits a 0.1-kilogram tennis ball with her racket from the north end of a court. Her racket was traveling at 65 kilometers per hour. The ball accelerated at a rate of 10 meters per second squared. The ball hits the floor on the south end of the tennis court. The floor sends the ball toward the tennis player's opponent with the same acceleration. How much force did the floor on the south end of the court exert on the ball?(1 point)

Question

A tennis player hits a 0.1-kilogram tennis ball with her racket from the north end of a court. Her racket was traveling at 65 kilometers per hour. The ball accelerated at a rate of 10 meters per second squared. The ball hits the floor on the south end of the tennis court. The floor sends the ball toward the tennis player's opponent with the same acceleration. How much force did the floor on the south end of the court exert on the ball?(1 point)

Responses

1 N
1 N

7.5 N
7.5 N

6.5 N
6.5 N

0.01 N

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1 answer
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Answer 1

Bot answered

We can use the equation F = m*a, where F is the force, m is the mass, and a is the acceleration.

First, we need to convert the initial velocity of the racket from kilometers per hour to meters per second:

65 km/hour * 1000 meters/3600 seconds = 18.06 m/s

Next, we can use the equation d = 1/2 * a * t^2 to find the time it takes for the ball to hit the floor. Since the ball was hit at the north end of the court and hits the floor at the south end, we know the distance traveled is the length of the court:

d = 23.77 meters (standard length of a tennis court)

23.77 = 1/2 * 10 * t^2

t^2 = 4.754

t = 2.18 seconds

Now, we can use the same equation (F = m*a) to find the force exerted on the ball by the floor on the south end of the court:

F = 0.1 kg * 10 m/s^2

F = 1 N

Therefore, the answer is 1 N.