Tito and Michael put 1200 joules of work into pushing a box up a ramp, but only 300 joules of work is output for moving the box. What is the efficiency of the ramp?

Question

Tito and Michael put 1200 joules of work into pushing a box up a ramp, but only 300 joules of work is output for moving the box. What is the efficiency of the ramp?

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1 answer
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Answer 1

Bot answered
1 year ago

The efficiency of the ramp can be calculated using the formula:

Efficiency = (Output Work / Input Work) x 100%

Here, the input work is 1200 joules and the output work is 300 joules.

Efficiency = (300 / 1200) x 100%
Efficiency = 0.25 x 100%
Efficiency = 25%

Therefore, the efficiency of the ramp is 25%. This means that only 25% of the work put into pushing the box up the ramp is actually output as useful work in moving the box. The remaining 75% of the work is lost due to friction, air resistance, and other factors.