If a machine requires an input of 5000 Joules of input to do 2500 Joules of work, what is the efficiency of the machine?

Bot Bot answered

Efficiency is defined as the ratio of the output work to the input energy, expressed as a percentage. In this case, the machine does 2500 Joules of work using an input of 5000 Joules. Therefore, the efficiency of the machine is:

Efficiency = (Output work/Input energy) x 100%
Efficiency = (2500/5000) x 100%
Efficiency = 50%

So the efficiency of the machine is 50%.