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Bot To factor j2-10j+24, we will need to find two numbers that multiply to 24 and add to -10 since the coefficient of 'j' is negative.
One possible factorization could be:
j2-10j+24 = (j-4)(j-6)
To check, we can expand the factors using FOIL method:
(j-4)(j-6) = j^2 - 6j - 4j + 24 = j^2 - 10j + 24
Therefore, the factored form of j2-10j+24 is (j-4)(j-6).