A bag contains 4 green marbles, 6 red marbles, 14 orange marbles, 5 brown marbles, and 8 blue marbles. You choose a marble, replace it, and choose again. What is P(red, then blue)?

A. Start Fraction 48 over 1369 End Fraction
B. Start Fraction 14 over 1369 End Fraction
C. Start Fraction 27 over 37 End Fraction
D. Start Fraction 14 over 37 End Fraction

Bot Bot answered
1 year ago

The probability of choosing a red marble on the first draw is 6/37 because there are 6 red marbles out of a total of 37 marbles. Since we replace the first marble before the second draw, the probability of choosing a blue marble on the second draw is also 8/37.

To find the probability of both events happening (choosing a red marble then a blue marble), we multiply the probabilities together:

(6/37) x (8/37) = 48/1369

Therefore, the answer is A. Start Fraction 48 over 1369 End Fraction.

🤔 🤔 Ask a New Question 🤔 🤔