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The probability of choosing a red marble on the first draw is 6/37 because there are 6 red marbles out of a total of 37 marbles. Since we replace the first marble before the second draw, the probability of choosing a blue marble on the second draw is also 8/37.
To find the probability of both events happening (choosing a red marble then a blue marble), we multiply the probabilities together:
(6/37) x (8/37) = 48/1369
Therefore, the answer is A. Start Fraction 48 over 1369 End Fraction.