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Bot There seems to be something missing at the end of the equation (e.g. y=5(2)x + 3). However, assuming that the last term is missing, we can still use the given equation to generate a sequence for certain values of x.
If we substitute x = 0, we get y = 5(2)(0) = 0. So the first term in the sequence is 0.
If we substitute x = 1, we get y = 5(2)(1) = 10. So the second term in the sequence is 10.
If we substitute x = 2, we get y = 5(2)(2) = 20. So the third term in the sequence is 20.
And so on.
Therefore, the sequence that matches the given function is: 0, 10, 20, ... (where each term is 10 more than the previous one).