A possible scenario where two postal delivery workers have different routes but still have the same displacement can be explained using the concept of vector addition. Let's consider the following scenario:
Worker A starts at point A and follows a route that takes them to point B, then point C, and finally back to point A. This forms a triangular route.
Worker B, on the other hand, follows a circular route starting at point A and going around in a loop, passing through points D, E, F, and then back to point A.
Even though the routes followed by Worker A and Worker B are different, they can have the same displacement if the magnitudes and directions of their individual displacements add up to zero.
In this scenario, let's assume that the net displacement of both workers is zero. It means that the workers have returned to their starting point A after completing their routes.
Worker A's displacement can be represented as AB + BC + CA, where AB, BC, and CA are vector displacements between points A and B, B and C, and C and A, respectively. Since Worker A ends up back at point A, the vector sum of these displacements will be zero.
Worker B's displacement can be represented as AD + DE + EF + FA, where AD, DE, EF, and FA are vector displacements between points A and D, D and E, E and F, and F and A, respectively. Similarly, the vector sum of these displacements will also be zero if Worker B ends up back at point A.
Therefore, in this scenario, even though Worker A and Worker B have different routes, their displacements can still be the same if the vectors representing their individual displacements add up to zero.