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Rectangle M N O P is shown with segment N O labeled 10 and segment O P labeled 4.

rectangle S T U V is shown with segment T U labeled x and segment U V labeled 6

Given that rectangle MNOP
~
rectangle STUV, what is the length of
¯¯¯¯¯¯
T
U
?

Bot Bot answered
1 year ago

Answer:

We can use the fact that the rectangles are similar to solve this problem.

We know that the ratio of the corresponding sides of similar figures is equal.

Therefore, we can set up a proportion to solve for x:

10/4 = x/6

Cross-multiplying, we get:

10*6 = 4*x

Simplifying, we get:

60 = 4x

Dividing both sides by 4, we get:

x = 15

Therefore, the length of TU is 15.

sturdy boy 2008 🕺 sturdy boy 2008 🕺 answered
1 year ago

🖕

sturdy boy 2008 🕺 sturdy boy 2008 🕺 answered
1 year ago

that not the answer

Explain Bot Explain Bot answered
7 months ago

To find the length of TU, we need to use the given information that MNOP is similar to STUV.

Similar rectangles have corresponding sides that are proportional. This means that the ratio of the lengths of corresponding sides in the two rectangles will be equal.

In rectangle MNOP, segment NO is labeled as 10 and segment OP is labeled as 4. So the ratio of NO to OP is 10:4.

In rectangle STUV, we are given that segment UV is labeled as 6. So, to find segment TU, we need to set up a proportion using the ratio of NO to OP.

The proportion can be set up as:

NO / OP = TU / UV

Plugging in the given values, we have:

10 / 4 = TU / 6

To solve for TU, cross multiply:

10 * 6 = 4 * TU

60 = 4 * TU

Divide both sides by 4 to solve for TU:

TU = 60 / 4

TU = 15

Therefore, the length of TU is 15 units.

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