Question

5. Find the surface area for the following net.

4 cm
6 cm
5 cm
10 cm

O 184 cm²
O 200 cm²
O 120 cm²
O 174 cm²

Answer 1

[AI-generated answer — Bot]

O 174 cm²

Answer 2

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Answer 3

[AI-generated answer — Step-by-Step Bot]

To find the surface area of a net or a 3-dimensional shape, we need to calculate the area of each face and then sum them up.

The given net has 4 sides with the following dimensions:
Side 1: 4 cm by 6 cm
Side 2: 4 cm by 5 cm
Side 3: 5 cm by 10 cm
Side 4: 5 cm by 10 cm

To calculate the surface area, we'll calculate the area of each face and then add them together.

Area of side 1 = 4 cm * 6 cm = 24 cm²
Area of side 2 = 4 cm * 5 cm = 20 cm²
Area of side 3 = 5 cm * 10 cm = 50 cm²
Area of side 4 = 5 cm * 10 cm = 50 cm²

Adding up all the areas:
Surface area = Area of side 1 + Area of side 2 + Area of side 3 + Area of side 4
Surface area = 24 cm² + 20 cm² + 50 cm² + 50 cm²
Surface area = 144 cm²

Therefore, the surface area of the given net is 144 cm².

Answer 4

[AI-generated answer — Explain Bot]

To find the surface area of the given net, we need to calculate the areas of all the individual faces and then sum them up.

The given net consists of four rectangular faces. Let's label the dimensions of these rectangles using the provided numbers:

1. Rectangle A:
Length = 4 cm
Width = 6 cm

2. Rectangle B:
Length = 4 cm
Width = 5 cm

3. Rectangle C:
Length = 5 cm
Width = 10 cm

4. Rectangle D:
Length = 5 cm
Width = 6 cm

To find the area of a rectangle, we multiply its length by its width. Using this formula, we can calculate the areas of the four rectangles:

Area of Rectangle A = Length × Width = 4 cm × 6 cm = 24 cm²
Area of Rectangle B = Length × Width = 4 cm × 5 cm = 20 cm²
Area of Rectangle C = Length × Width = 5 cm × 10 cm = 50 cm²
Area of Rectangle D = Length × Width = 5 cm × 6 cm = 30 cm²

Now, we sum up the areas of all the rectangles to get the total surface area:

Total Surface Area = Area of Rectangle A + Area of Rectangle B + Area of Rectangle C + Area of Rectangle D
= 24 cm² + 20 cm² + 50 cm² + 30 cm²
= 124 cm²

Therefore, the surface area of the given net is 124 cm².

None of the provided answer choices match this result.