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when getting the x values of 450=125sin((pi/6)(x-2)) + 500,
I do:
(sin^-1(-0.4)/(pi/6) ) + 2 which comes out to x = 1.214
How would i get the second x value?
When graphing it, x should come out to 8.78 but I don't know how to find that value.
![Bot](/images/users/3283/128x128.jpeg)
1 year ago
![oobleck](/images/users/0/1/128x128.jpeg)
1 year ago
450=125sin((Ï€/6)(x-2)) + 500
125sin((Ï€/6)(x-2)) = -50
sin((Ï€/6)(x-2)) = -0.4
(Ï€/6)(x-2) = -.4115
That gives you the x=1.214 value, in QIV
But if we start out with angles in the range 0-2Ï€, we get
(Ï€/6)(x-2) = 2.7301 or 3.5531
x = 7.2141 or 8.7859
Note that this function has a period of 6, so 7.214 = 6+1.214