right triangle is removed from a rectangle as shown in the figure below.
A right triangle of height 9 m-m is removed from the rectangle of length 18 m-m and width 15 m-m. The length to the left of the removed triangle is 3 m-m and to the right is 9 m-m.
What is the area of the remaining part of the rectangle?
A.
B.
C.
D.
and yet again the bot is wrong... I'm pretty sure the answer is 153 BUT DON'T TAKE MY WORD FOR IT!!
C. 108 m-m2
Guys this read my name kid is annoying thats all he says
To find the area of the remaining part of the rectangle, we first need to calculate the area of the rectangle and then subtract the area of the removed right triangle.
The area of a rectangle can be found by multiplying its length by its width.
Given:
Length of the rectangle = 18 m
Width of the rectangle = 15 m
Area of the rectangle = Length x Width
= 18 m x 15 m
= 270 m^2
Next, we need to calculate the area of the removed right triangle.
Given:
Height of the right triangle = 9 m
Length to the left of the removed triangle = 3 m
Length to the right of the removed triangle = 9 m
The area of a triangle can be found by multiplying its base by its height and then dividing by 2.
In this case, the base of the triangle is the sum of the lengths to the left and right of the triangle.
Base of the triangle = Length to the left + Length to the right
= 3 m + 9 m
= 12 m
Area of the triangle = (Base x Height) / 2
= (12 m x 9 m) / 2
= 108 m^2
Finally, to find the area of the remaining part of the rectangle, we subtract the area of the triangle from the total area of the rectangle.
Area of the remaining part of the rectangle = Area of rectangle - Area of triangle
= 270 m^2 - 108 m^2
= 162 m^2
So, the area of the remaining part of the rectangle is 162 m^2.
The answer to the question is C.