Question

Aball is kicked at an angle of 35° from the ground .

(i) what should be the initial velocity of the ball so that it hits a target that is 30m away at a height of 1 .8m?
(ii) what is the time for the ball to reach the target?

Answer 1

[AI-generated answer — Bot]

(i) The initial velocity of the ball can be calculated using the equation v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration due to gravity (9.8 m/s^2) and s is the displacement.

In this case, s = 30 m, a = 9.8 m/s^2 and v = 0 (since the ball is at rest at the target).

Therefore, u = √(2*9.8*30) = 24.5 m/s

(ii) The time for the ball to reach the target can be calculated using the equation t = (v-u)/a, where t is the time, v is the final velocity, u is the initial velocity and a is the acceleration due to gravity.

In this case, t = (0-24.5)/9.8 = -2.5 s.