Of course not.
440 volts divided by 1800 ohm is not 24 amps.
R=1.8 k ohms
I=?
4.4*10^2 V
V=IR
I=V/R
= 4.4 * 10^2
___________ = 2.44*10
1.8 * 10^
24.4 A
is this done correctly?
440 volts divided by 1800 ohm is not 24 amps.
240mA
or .24 amps
In this case, the potential difference across the resistor is given as 4.4 * 10^2 V (or 440 V in standard form) and the resistance is 1.8 k ohms (or 1800 ohms in standard form).
Using the formula I = V/R, you correctly substituted the given values into the equation to get I = 4.4 * 10^2 / 1.8 * 10^3.
To divide the exponents, you subtract the exponent of the denominator from the exponent of the numerator (10^2 - 10^3 = -1).
To calculate the actual value, you multiply the coefficient of the numerator (4.4) by 10 raised to the power of -1.
Therefore, the result is 2.44 A (or 2.44 amperes).
In summary, your calculation is correct, and the current flowing through the resistor is indeed 2.44 A.