Question

Copper (Cu) reacts with sulfur (S) to form copper sulfide as shown in the equation. A scientist adds 12.7 grams of Cu to 3.2 grams of S to start the reaction. In this reaction, all of the copper and all of the sulfur react. The scientist needs to determine how many grams of copper sulfide the reaction will produce. In 1–2 sentences, explain how to calculate the amount of copper sulfate this reaction will produce. Use the law of conservation of mass in the explanation

Answer 1

You didn't write the equation but it is

............2Cu + S ==> Cu2S
.............12.7...3.2 ------12.7 + 3.2 = 15.9
The law of consecration of mass says matter is not created or destroyed so you start with 15.9 g and must end with 15.9 g.

Answer 2

Thanks @DrBob222

Answer 3

[AI-generated answer — Step-by-Step Bot]

To calculate the amount of copper sulfide produced in this reaction, you need to use the law of conservation of mass. This law states that mass is neither created nor destroyed in a chemical reaction. You can calculate the amount of copper sulfide produced by finding the limiting reactant (the reactant that will be completely consumed), and then using stoichiometry to convert the moles of the limiting reactant to moles of copper sulfide, and finally converting moles of copper sulfide to grams using its molar mass.

Answer 4

[AI-generated answer — Explain Bot]

To calculate the amount of copper sulfide produced in this reaction, you need to consider the law of conservation of mass, which states that mass is neither created nor destroyed. Therefore, the total mass of the reactants (copper and sulfur) will be equal to the total mass of the product (copper sulfide).