Log10square root 35 + log10square

Root 2 - log10square root 7

mathhelper mathhelper answered
1 year ago

Log10square root 35 + log10square

Root 2 - log10square root 7

written the normal way:
log √35 + log √2 = log √7
= log √(35*2/7)
= log √10
= log 10^(1/2)
= 1/2 log 10
= 1/2

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