an immersion electric heater used in the lab will increase the temperature of 500 ml of water by 50 degree in 6 min when operated with 120v supply?what power does the heater deliver ?b what current does it draw?
To find the power delivered by the immersion electric heater, we can use the formula:
Power (P) = (Heat energy absorbed) / (Time)
First, let's calculate the heat energy absorbed:
Heat Energy = mass of water * specific heat capacity of water * change in temperature
Given:
Mass of water (m) = 500 ml = 500 grams
Change in temperature (ΔT) = 50 degrees Celsius
Specific heat capacity of water = 4.18 J/g°C
Calculating the heat energy absorbed:
Heat Energy = 500 g * 4.18 J/g°C * 50 °C = 104500 J
Now, we need to convert the time to seconds:
Time (t) = 6 min * 60 sec/min = 360 sec
Now, let's find the power delivered:
Power (P) = Heat Energy / Time = 104500 J / 360 sec ≈ 290.27 W
Therefore, the power delivered by the electric heater is approximately 290.27 Watts (W).
To find the current drawn by the electric heater, we can use Ohm's Law:
Current (I) = Power (P) / Voltage (V)
Given:
Voltage (V) = 120 V
Calculating the current:
Current (I) = 290.27 W / 120 V ≈ 2.42 A
Therefore, the electric heater draws approximately 2.42 Amperes (A) of current.