A cylindrical drum (2 ft diameter, 3 ft high) is filled with fluid whose density is 40 lb/ft3. Determine (a) the total volume of the fluid , (b) its total mass in pounds and in slugs, (c) its specific weight where g= 31.9fps2 (d) its specific volume.

a. Volume = pir^2h = 3.14 x 1 ft x 3 = ? ft^3

b. mass = volume x density. You have volume from above and density in the problem. For slugs, multiply mass in pounds x 0.0311 = ?
c. specific weight = density x 31.9 = ?
d. specific volume = volume/mass = ?

Did you know?

Did you know that the total volume of fluid in a cylindrical drum (2 ft diameter, 3 ft high) can be determined using the formula for the volume of a cylinder? By multiplying the cross-sectional area (πr^2) with the height (3 ft), we can find the total volume of the fluid. To calculate the total mass of the fluid in pounds, we need to multiply the density of the fluid (40 lb/ft3) by the total volume of the fluid obtained in the previous step. This will give us the mass in pounds. However, if we are interested in determining the mass in slugs, we need to divide the total mass in pounds by the acceleration due to gravity (32.2 ft/s^2). This ratio is known as the mass in slugs. The specific weight of the fluid can be calculated by multiplying the density of the fluid by the acceleration due to gravity (31.9 ft/s^2). This gives us the weight per unit volume, expressed in pounds per cubic foot. Finally, the specific volume of the fluid is obtained by dividing the reciprocal of the density of the fluid (1/density). This value represents the volume occupied by a unit mass of the fluid. These calculations allow us to understand various properties of the fluid in the cylindrical drum, such as its volume, mass, weight, and the amount of space it occupies per unit mass.

A cylindrical drum (2 ft diameter, 3 ft high) is filled with fluid whose density is 40 lb/ft3. Determine (a) the total volume of the fluid , (b) its total mass in pounds and in slugs, (c) its specific weight where g= 31.9fps2 (d) its specific volume.

a. Volume = pi*r^2*h = 3.14 x 1 ft x 3 = ? ft^3

a. Volume = pir^2h = 3.14 x 1 ft x 3 = ? ft^3