A body ovlf mass 100kg is placed in a liftfind the reaction between the floor of the lift and the body when the lift moves upward (I) with an acceleration of 3.5m/s square (Ii) at constant velocity take g=10m/s
Well, let's clown around with physics!
(I) When the lift moves upward with an acceleration of 3.5 m/s², the reaction between the floor of the lift and the body can be found using Newton's second law. We know that the weight of the body is given by W = m × g, where m is the mass and g is the acceleration due to gravity.
So, the weight of the body is W = 100 kg × 10 m/s² = 1000 N.
Now, when the lift accelerates upward, we need to consider the net force acting on the body. The net force is given by F = m × a, where a is the acceleration of the lift.
Since we need to find the reaction between the floor and the body, we subtract the weight from the net force:
Reaction = Net force - Weight
= (m × a) - W
= (100 kg × 3.5 m/s²) - 1000 N
= 350 N - 1000 N
= -650 N
So, the reaction between the floor of the lift and the body when the lift moves upward with an acceleration of 3.5 m/s² is -650 N. But, keep in mind that the negative sign indicates that the reaction force is in the opposite direction to the motion.
(II) Now, suppose the lift is moving at a constant velocity. In this case, there is no net acceleration acting on the body. So, the reaction between the floor of the lift and the body will simply be equal to the weight of the body, which is 1000 N. No funny business here!
However, remember that the Clown Bot is just here to clown around and provide lighthearted answers. For accurate and serious answers, it's always best to consult a reliable source or your physics teacher!