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Help on titration concerning molarity

Carson Carson answered

Concerning?

Bright Bright answered

I need the explaination now

Carson Carson answered

Use the titration formula. If the titrant and analyte have a 1:1 mole ratio, the formula is molarity (M) of the acid x volume (V) of the acid = molarity (M) of the base x volume (V) of the base. (Molarity is the concentration of a solution expressed as the number of moles of solute per litre of solution.)

Arsal Arsal answered

Use the titration formula. If the titrant and analyte have a 1:1 mole ratio, the formula is molarity (M) of the acid x volume (V) of the acid = molarity (M) of the base x volume (V) of the base. (Molarity is the concentration of a solution expressed as the number of moles of solute per litre of solution.)Use the titration formula. If the titrant and analyte have a 1:1 mole ratio, the formula is molarity (M) of the acid x volume (V) of the acid = molarity (M) of the base x volume (V) of the base. (Molarity is the concentration of a solution expressed as the number of moles of solute per litre of solution.)Use the titration formula. If the titrant and analyte have a 1:1 mole ratio, the formula is molarity (M) of the acid x volume (V) of the acid = molarity (M) of the base x volume (V) of the base. (Molarity is the concentration of a solution expressed as the number of moles of solute per litre of solution.)Use the titration formula. If the titrant and analyte have a 1:1 mole ratio, the formula is molarity (M) of the acid x volume (V) of the acid = molarity (M) of the base x volume (V) of the base. (Molarity is the concentration of a solution expressed as the number of moles of solute per litre of solution.)Use the titration formula. If the titrant and analyte have a 1:1 mole ratio, the formula is molarity (M) of the acid x volume (V) of the acid = molarity (M) of the base x volume (V) of the base. (Molarity is the concentration of a solution expressed as the number of moles of solute per litre of solution.)Use the titration formula. If the titrant and analyte have a 1:1 mole ratio, the formula is molarity (M) of the acid x volume (V) of the acid = molarity (M) of the base x volume (V) of the base. (Molarity is the concentration of a solution expressed as the number of moles of solute per litre of solution.)Use the titration formula. If the titrant and analyte have a 1:1 mole ratio, the formula is molarity (M) of the acid x volume (V) of the acid = molarity (M) of the base x volume (V) of the base. (Molarity is the concentration of a solution expressed as the number of moles of solute per litre of solution.)Use the titration formula. If the titrant and analyte have a 1:1 mole ratio, the formula is molarity (M) of the acid x volume (V) of the acid = molarity (M) of the base x volume (V) of the base. (Molarity is the concentration of a solution expressed as the number of moles of solute per litre of solution.)Use the titration formula. If the titrant and analyte have a 1:1 mole ratio, the formula is molarity (M) of the acid x volume (V) of the acid = molarity (M) of the base x volume (V) of the base. (Molarity is the concentration of a solution expressed as the number of moles of solute per litre of solution.)Use the titration formula. If the titrant and analyte have a 1:1 mole ratio, the formula is molarity (M) of the acid x volume (V) of the acid = molarity (M) of the base x volume (V) of the base. (Molarity is the concentration of a solution expressed as the number of moles of solute per litre of solution.)Use the titration formula. If the titrant and analyte have a 1:1 mole ratio, the formula is molarity (M) of the acid x volume (V) of the acid = molarity (M) of the base x volume (V) of the base. (Molarity is the concentration of a solution expressed as the number of moles of solute per litre of solution.)Use the titration formula. If the titrant and analyte have a 1:1 mole ratio, the formula is molarity (M) of the acid x volume (V) of the acid = molarity (M) of the base x volume (V) of the base. (Molarity is the concentration of a solution expressed as the number of moles of solute per litre of solution.)Use the titration formula. If the titrant and analyte have a 1:1 mole ratio, the formula is molarity (M) of the acid x volume (V) of the acid = molarity (M) of the base x volume (V) of the base. (Molarity is the concentration of a solution expressed as the number of moles of solute per litre of solution.)Use the titration formula. If the titrant and analyte have a 1:1 mole ratio, the formula is molarity (M) of the acid x volume (V) of the acid = molarity (M) of the base x volume (V) of the base. (Molarity is the concentration of a solution expressed as the number of moles of solute per litre of solution.)Use the titration formula. If the titrant and analyte have a 1:1 mole ratio, the formula is molarity (M) of the acid x volume (V) of the acid = molarity (M) of the base x volume (V) of the base. (Molarity is the concentration of a solution expressed as the number of moles of solute per litre of solution.)Use the titration formula. If the titrant and analyte have a 1:1 mole ratio, the formula is molarity (M) of the acid x volume (V) of the acid = molarity (M) of the base x volume (V) of the base. (Molarity is the concentration of a solution expressed as the number of moles of solute per litre of solution.)Use the titration formula. If the titrant and analyte have a 1:1 mole ratio, the formula is molarity (M) of the acid x volume (V) of the acid = molarity (M) of the base x volume (V) of the base. (Molarity is the concentration of a solution expressed as the number of moles of solute per litre of solution.)

DrBob222 DrBob222 answered

What's all this "repeating" jazz. Once is enough.

Here is the procedure for calculating titration data.
1. Write the equation and balance it.
2. Calculate moles of the titrant. Moles = M x L = ?
3. Using the coefficients in the balanced equation from step 1 above, convert mols titrant to mols of what you have titrated.
4. Then M of the unknown acid/base = moles from step 3/L of the unknown
Why not post a problem, show the steps, ask questions about what you don't understand, and let us walk you through it? Unfortunately no one teaches normality anymore but that is the way to go since mLacid x Nacid = mLbase x Nbase ALWAYS works EVERY TIME and you don't need to go through step 3 above. I think the IUPAC is short sighted in the recommendation to cut normality from the curriculum. But then, who am I with no clout?

Explain Bot Explain Bot answered

Sure! I can help you with titration and molarity.

Titration is a technique used in chemistry to determine the concentration of a solution (known as the analyte) by reacting it with a solution of known concentration (known as the titrant). Molarity, on the other hand, is a measure of concentration and represents the number of moles of solute (substance being dissolved) per liter of solution.

To calculate the molarity of a solution, you need to know the number of moles of solute and the volume of the solution. The formula for molarity (M) is:

Molarity (M) = Moles of solute / Volume of solution (in liters)

So, to determine the molarity of a solution, you can follow these steps:

1. Determine the number of moles of solute: This can be done using the molar mass of the solute and the mass or volume of the solute used in the solution.

2. Measure the volume of the solution: This is usually done using a graduated cylinder or a burette.

3. Convert the volume to liters: If the volume is given in milliliters (mL), divide it by 1000 to convert it to liters.

4. Use the formula: Divide the number of moles of solute by the volume of the solution (in liters) to find the molarity.

For example, let's say you have a solution containing 0.25 moles of solute and a total volume of 0.5 liters. To calculate the molarity, you would use the formula:

Molarity (M) = 0.25 moles / 0.5 liters = 0.5 M

This means that the molarity of the solution is 0.5 M.

Remember, when performing a titration, you need to carefully measure the volumes of both the titrant and analyte, and determine the volume at which the reaction is complete (known as the equivalence point) to accurately calculate the molarity of the analyte.

I hope this helps! Let me know if you have any other questions.