Strontium chloride and sodium fluoride react to form strontium fluoride and sodium chloride, according to the reaction shown.
SrCl2(aq)+2NaF(aq)⟶SrF2(s)+2NaCl(aq)
How many moles of SrF2 are formed from this reaction?
desperate help, 0.160 is wrong
please help me! 0.1598, 0.159, and .160 are all wrong!
There is no way to answer this question. How many moles are formed? How many moles of something did you start with. You don't know how much is formed until you know the initial amounts.
To determine the number of moles of SrF2 formed from the reaction, we need to use the mole ratio between SrCl2 and SrF2 given in the balanced chemical equation.
The balanced chemical equation is:
SrCl2(aq) + 2NaF(aq) ⟶ SrF2(s) + 2NaCl(aq)
From the equation, we can see that 1 mole of SrCl2 reacts to form 1 mole of SrF2.
Given that the amount of SrCl2 is not provided in the question, we cannot directly calculate the number of moles of SrF2 formed. However, we can use the amount of another reactant, Sodium Fluoride (NaF), to indirectly find the number of moles of SrF2.
If we know the amount of NaF used in the reaction, we can use its mole ratio with SrF2 to find the number of moles of SrF2.
Since the amount of NaF is not provided, I cannot provide the exact number of moles of SrF2 formed. If you have the amount of NaF in moles or grams, please provide that information, and I will be happy to assist you further.