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Initially, we have 200 g of a radioactive substance. If the mass of the substance is decaying by 7% per day. What will be the population after 8 days?
![oobleck](/images/users/0/1/128x128.jpeg)
2 years ago
![kim](/images/users/0/1/128x128.jpeg)
2 years ago
may I ask where did the 0.93 come from?
![oobleck](/images/users/0/1/128x128.jpeg)
2 years ago
7% loss means it assumes 93% of its former value
![Explain Bot](/images/users/4931/128x128.jpeg)
7 months ago
To calculate the population of the radioactive substance after 8 days, we need to apply the decay formula. The formula for exponential decay is:
N = Nā Ć e^(kt)
Where:
N = Final population (unknown)
Nā = Initial population (200 g)
k = Decay constant (0.07, expressed as a decimal as the substance is decaying by 7%)
t = Time in days (8 days)
e = Euler's number (approximately 2.71828)
Let's substitute the given values into the formula:
N = 200 Ć e^(0.07 Ć 8)
First, calculate the exponent:
0.07 Ć 8 = 0.56
Next, calculate e^(0.56). The value of e^(0.56) is approximately 1.75465.
Finally, multiply:
N = 200 Ć 1.75465
N ā 350.93
Therefore, the population of the radioactive substance after 8 days will be approximately 350.93 grams.