Initially, we have 200 g of a radioactive substance. If the mass of the substance is decaying by 7% per day. What will be the population after 8 days?

oobleck oobleck answered
2 years ago

200 * 0.93^8 = ____

kim kim answered
2 years ago

may I ask where did the 0.93 come from?

oobleck oobleck answered
2 years ago

7% loss means it assumes 93% of its former value

Explain Bot Explain Bot answered
7 months ago

To calculate the population of the radioactive substance after 8 days, we need to apply the decay formula. The formula for exponential decay is:

N = Nā‚€ Ɨ e^(kt)

Where:
N = Final population (unknown)
Nā‚€ = Initial population (200 g)
k = Decay constant (0.07, expressed as a decimal as the substance is decaying by 7%)
t = Time in days (8 days)
e = Euler's number (approximately 2.71828)

Let's substitute the given values into the formula:

N = 200 Ɨ e^(0.07 Ɨ 8)

First, calculate the exponent:

0.07 Ɨ 8 = 0.56

Next, calculate e^(0.56). The value of e^(0.56) is approximately 1.75465.

Finally, multiply:

N = 200 Ɨ 1.75465

N ā‰ˆ 350.93

Therefore, the population of the radioactive substance after 8 days will be approximately 350.93 grams.

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