Use the method of cylindrical shells to find the volume V generated by rotating the region bounded by the given curves about the y-axis.

y = 9e^−x^2, y = 0, x = 0, x = 1

v = ∫[0,1] 2πrh dx

where r = x and h = y = 9e^(-x^2)
v = ∫[0,1] 2πx*9e^(-x^2) dx
use u = -x^2, du = -2x dx and you have
v = ∫[0,-1] -9πe^u du

To find the volume generated by rotating the given region about the y-axis using the method of cylindrical shells, follow the steps below:

Step 1: Determine the limits of integration.
The region is bounded by y = 0, x = 0, and x = 1. Since we are rotating about the y-axis, we need to determine the limits of integration in terms of y.
From the equation y = 0, we know that the lower limit of integration for y is 0.
To find the upper limit of integration for y, we set the exponential equation y = 9e^(-x^2) equal to y and solve for x:
9e^(-x^2) = y
e^(-x^2) = y/9
-x^2 = ln(y/9)
x^2 = -ln(y/9)
x = ±√(-ln(y/9))
In this case, since x lies between 0 and 1, we only need the positive root: x = √(-ln(y/9))
Therefore, the upper limit of integration for y is √(-ln(y/9)).

Step 2: Determine the height of each cylindrical shell.
The height of each cylindrical shell is given by the difference between the x-values at the top and bottom of the region. In this case, the height of each shell is dx, the differential element for integration.

Step 3: Determine the radius of each cylindrical shell.
The radius of each cylindrical shell is the distance of the x-value from the y-axis. Since we are rotating about the y-axis, the radius is simply x.

Step 4: Write the integral expression for the volume.
The volume of each cylindrical shell is given by the formula: dV = 2πrhdx, where r is the radius and h is the height.
Therefore, the integral expression for the volume is:
V = ∫(from y = 0 to y = 9) 2πx(√(-ln(y/9))) dx.

Step 5: Evaluate the integral to find the volume.
Integrate the expression in step 4 with respect to x, using the limits of integration for y determined in step 1.
V = 2π ∫(from 0 to 9) x√(-ln(y/9)) dx

Note: The integration process involves calculating an antiderivative, which can be tedious and involve either trigonometric, logarithmic, or exponential functions.

Unfortunately, it is not possible for me to evaluate the integral step-by-step without a specific numerical range. You can use numerical methods or computer software to evaluate the integral and find the volume V.

To find the volume using the method of cylindrical shells, we need to integrate the formula for the volume of a cylindrical shell over the interval of interest.

The formula for the volume of a cylindrical shell is given by V = 2πrhΔx, where r is the distance from the axis of rotation to the shell, h is the height of the shell, and Δx is the thickness of the shell.

In this case, we are rotating the region bounded by the curves y = 9e^(-x^2), y = 0, x = 0, and x = 1 about the y-axis, so the axis of rotation is the y-axis.

To use the method of cylindrical shells, we need to express the variables r, h, and Δx in terms of y. Let's do that:

Since we are rotating about the y-axis, the distance r is simply the x-coordinate, so r = x.
The height h of each shell is given by the difference between the y-values of the two curves at a given x-value, so h = y - 0 = y.
The thickness of each shell, Δx, is given by the difference between two consecutive x-values, so Δx = dx.

Now that we have expressions for r, h, and Δx in terms of y, we can rewrite the formula for the volume of a cylindrical shell as V = 2πxy dx.

To find the limits of integration for y, we need to find the y-values of the curve intersections.

Setting the two equations equal to each other, we can solve for x:

9e^(-x^2) = 0

Since e^(-x^2) is always positive, we set 9e^(-x^2) equal to zero.

e^(-x^2) = 0

Taking the natural logarithm of both sides, we get:

-x^2 = ln(0)

However, the natural logarithm of zero is undefined, so there are no intersection points with the y-axis.

Since the curve y = 9e^(-x^2) is always positive, it will always be the upper curve, and the lower bound for the integration will be y = 0.

The upper bound for the integration will be the y-value of the curve at x = 1, which is y = 9e^(-1^2) = 9e^(-1).

Therefore, the integral for the volume of the region is:

V = ∫[0, 9e^(-1)] 2πxy dx

We can now evaluate this integral to find the volume of the region.