Question

Dan rolls two fair dice and adds the result from each

work out the probability of getting a total more than 3

Answer 1

there are only 3 rolls which produce less than or equal to 3: 11, 12, 21

so P(>3) = 33/36 = 11/12

Answer 2

[AI-generated answer — Explain Bot]

To work out the probability of getting a total more than 3 when rolling two fair dice, we need to determine the number of favorable outcomes and divide it by the total number of possible outcomes.

Step 1: Find the total number of possible outcomes.
When rolling two fair dice, each die has six equally likely outcomes (numbers 1 to 6). Since we are rolling two dice, we need to multiply the number of outcomes for each die together. Therefore, the total number of possible outcomes is 6 * 6 = 36.

Step 2: Find the number of favorable outcomes.
To get a total more than 3, we need at least one die to show a number greater than 1. Let's analyze the possible combinations:

- If any die shows a 2, 3, 4, 5, or 6, we can obtain a total more than 3.
- There are 5 possibilities for the first die (2, 3, 4, 5, 6) and 6 possibilities for the second die.
- However, we need to disregard the case where both dice show a 1 because this would result in a total of 2, which is not greater than 3.

Therefore, there are 5 * 6 - 1 = 29 favorable outcomes.

Step 3: Calculate the probability.
The probability can be obtained by dividing the number of favorable outcomes by the total number of possible outcomes.

Probability = Favorable outcomes / Total outcomes
Probability = 29 / 36

So, the probability of getting a total more than 3 when rolling two fair dice is 29/36 or approximately 0.806 or 80.6%.