Question

a fair spinner has 9 equal sections 3 red 2 blue and 4 green

it is spun twice
what is the probablity of not getting two consecutive reds

Answer 1

whats the answer

Answer 2

Did you even look at the solution I gave you for your previous post ??

I am more concerned that you know how to do these kind of question, than having the "answer".

Answer 3

i need the answer thats all

Answer 4

[AI-generated answer — Explain Bot]

To find the probability of not getting two consecutive reds after spinning the fair spinner twice, we can break it down into two cases:

Case 1: Not getting a red on the first spin
Since there are a total of 9 sections on the spinner and 3 of them are red, the probability of not getting a red on the first spin is (9 - 3)/9 = 6/9 = 2/3.

Case 2: Getting a red on the first spin but not getting a red on the second spin
In this case, after getting a red on the first spin, there are now only 2 red sections left out of a total of 8 sections (9 sections minus the one already spun). Therefore, the probability of not getting a red on the second spin is 6/8 = 3/4.

To find the overall probability, we need to multiply the probabilities of the individual cases, since both of them need to happen:
P(not getting two consecutive reds) = P(not getting a red on the first spin) * P(not getting a red on the second spin)
P(not getting two consecutive reds) = (2/3) * (3/4)
P(not getting two consecutive reds) = 6/12
P(not getting two consecutive reds) = 1/2

Therefore, the probability of not getting two consecutive reds after spinning the fair spinner twice is 1/2 or 50%.