well, if 3 of the 11 are green, then 8 must be not-green.
Prob(not green, then green) = (8/11)(3/11) = 24/121
it is spun twice
what is the probability of getting not green then green
Prob(not green, then green) = (8/11)(3/11) = 24/121
Probability of not getting green on the first spin:
There are a total of 11 sections on the spinner, and 3 of them are green. Therefore, the probability of not getting green on the first spin is (11 - 3) / 11 = 8 / 11.
Probability of getting green on the second spin:
After the first spin, there are 10 sections remaining, and 3 of them are green. Therefore, the probability of getting green on the second spin is 3 / 10.
To calculate the overall probability, we multiply these two probabilities together:
Probability of not green then green = (8 / 11) * (3 / 10) = 24 / 110 = 12 / 55.
Therefore, the probability of getting not green on the first spin and green on the second spin is 12 / 55.
The total number of possible outcomes for the first spin is 11 since there are 11 equal sections on the spinner.
Since there are 3 green sections out of the total 11 sections, the probability of the first spin landing on a green section is 3/11.
Once the first spin lands on a non-green section, there will be 10 remaining sections in the spinner, out of which 2 are green. Therefore, the probability of the second spin landing on a green section is 2/10.
To find the probability of both events occurring together (not green then green), we multiply the probabilities of each event. Hence, the probability of getting not green then green is (3/11) * (2/10) = 6/110.
Therefore, the probability of getting not green then green is 6/110, which can also be simplified to 3/55.