Use your knowledge of valence electrons and how they affect bonds to figure out how carbon (Group 14) and oxygen (Group 16) would be attached to one another. In carbon dioxide (CO2), how is the compound structured? (Use “–” to represent a single bond and “=” to represent a double bond.)
A. O=C=O
B. C–O–O
C. O=C–O
D. C=O–O
Anyone know the answers to this quick check?
1. Two
2. An atom wants a full outer shell of valence electrons
3. O=C=O
4. No, because needs four bonds
5. H-O-O-H
Thank you for saving Lives Bruh
Well, let me clown around with this question for you! When carbon (Group 14) and oxygen (Group 16) get together to form carbon dioxide, the compound is structured as option A, O=C=O. Why? Because carbon has four valence electrons and oxygen has six valence electrons, so carbon needs two electrons to fulfill its octet and oxygen needs four electrons. By sharing two pairs of electrons, they can both reach a happy octet! So, they form a nifty double bond, making carbon dioxide look like a funny little molecule with two oxygen atoms double-bonded to a carbon atom. Voila, carbon dioxide!
To determine how carbon and oxygen are attached to each other in carbon dioxide (CO2), we need to consider their valence electrons and the Octet Rule.
Carbon is in Group 14, so it has 4 valence electrons. Oxygen is in Group 16 and has 6 valence electrons. Both carbon and oxygen want to achieve a stable configuration with 8 valence electrons.
In a carbon dioxide molecule (CO2), we have a total of 16 valence electrons (4 from carbon and 6x2 from oxygen). Since oxygen is more electronegative than carbon, oxygen will attract electrons more strongly.
To satisfy the Octet Rule for both carbon and oxygen, we need to form double bonds between the carbon atom and each oxygen atom. Each bond consists of two electrons.
So, the correct structure for carbon dioxide (CO2) is:
A. O=C=O
In this structure, one oxygen atom forms a double bond with the central carbon atom, and the other oxygen atom forms another double bond with the central carbon atom.