100km/hr = 0 + 4 s * a
a =100/4 = 25 km/ hr s
v = v0 + at
A car company advertises that a certain model of car can go from 0 to 100 km/h in 4 seconds. What is the car’s acceleration?
400 km/hr/s
0.04 km/hr/s
25 km/hr/s
96 km/hr/s
a =100/4 = 25 km/ hr s
Substituting these values into the equation, we have:
100 km/hr = 0 km/hr + a * 4 sec
Simplifying the equation, we get:
100 km/hr = 4a
To solve for "a", we divide both sides of the equation by 4:
100 km/hr ÷ 4 = 4a ÷ 4
25 km/hr = a
Therefore, the car's acceleration is 25 km/hr/s.
Given: v0 = 0 km/h (initial velocity), v = 100 km/h (final velocity), and t = 4 seconds (time).
First, we need to convert the velocities from km/h to km/s, as we want the acceleration in km/h/s.
v0 = 0 km/h = 0 km/h * (1 hour/3600 seconds) = 0 km/s
v = 100 km/h = 100 km/h * (1 hour/3600 seconds) = (100/3600) km/s
Now, substitute these values into the equation:
v = v0 + at
(100/3600) km/s = 0 km/s + a * 4 seconds
To isolate 'a' (acceleration), we can multiply both sides of the equation by 4 seconds:
(100/3600) km/s * 4 seconds = a * 4 seconds * 4 seconds
Simplifying:
(400/3600) km = a * 16 seconds
Dividing both sides by 16 seconds:
(400/3600) km/16 s = a
a ≈ 0.044 km/hr/s
So, the car's acceleration is approximately 0.044 km/hr/s. Therefore, the nearest answer among the provided options is 0.04 km/hr/s.