Write a balanced chemical equation based on the following description:
liquid C₇H₈O is burned with oxygen gas to produce gaseous carbon dioxide and water vapor
2C7H8O(l) +17O2(g) ==> 14CO2(g) + 8H2O(g)
Sure, let's do some chemical comedy! Here's the balanced equation for the fiery reaction you described:
C₇H₈O (liquid) + 9 O₂ (gas) → 7 CO₂ (gas) + 4 H₂O (gas)
Now remember, it's a good idea to do this experiment in a well-ventilated area and under controlled conditions. Safety first, folks!
The balanced chemical equation for the combustion of liquid C₇H₈O with oxygen gas can be written as follows:
C₇H₈O + 9O₂ → 7CO₂ + 4H₂O
To write a balanced chemical equation, we need to ensure that the number of atoms on each side of the equation is the same.
The given description provides the reactants and the products involved in the reaction:
Reactants: C₇H₈O (liquid) and oxygen gas (O₂)
Products: carbon dioxide (CO₂) and water vapor (H₂O)
Now, let's write the balanced chemical equation:
C₇H₈O + O₂ → CO₂ + H₂O
To balance the equation, we need to ensure that the number of each type of atom is the same on both sides of the equation.
First, let's start by balancing the carbon atoms. We have 1 carbon atom on the left side (C₇H₈O) and 1 carbon atom on the right side (CO₂).
Next, let's balance the hydrogen atoms. We have 8 hydrogen atoms on the left side (C₇H₈O) and 2 hydrogen atoms on the right side (H₂O). To balance them, we can add a coefficient of 4 in front of the water vapor:
C₇H₈O + O₂ → CO₂ + 4H₂O
Lastly, let's balance the oxygen atoms. We have 2 oxygen atoms on the left side (O₂) and 6 oxygen atoms on the right side (4 in CO₂ and 2 in H₂O). To balance them, we can add a coefficient of 7/2 (or 3.5) in front of the oxygen gas:
C₇H₈O + 3.5O₂ → CO₂ + 4H₂O
Since we can't have a fractional coefficient, let's multiply all coefficients by 2 to get whole numbers:
2C₇H₈O + 7O₂ → 14CO₂ + 16H₂O
Therefore, the balanced chemical equation is:
2C₇H₈O + 7O₂ → 14CO₂ + 16H₂O