A line has a slope of –5 and a y-intercept of 9. What is the equation of the line in standard form?
Please answer!!
slope-intercept ... y = -5x + 9
adding 5x ... 5x + y = 9
Most authors of textbooks label them as follows
y = 6x -9 <----- y-intercept slope form
3x + 5y = 2 <---- standard form
6x - 2y + 7 = 0 <------ general form
check which notation your text uses.
You must practise to form one format into any of the other two.
in your case, from the given, we can immediately say
y = -5x + 9
or
5x + y = 9
or 5x + y - 9 = 0
To find the equation of a line in standard form, we need to use the slope-intercept form of a line, which is given by y = mx + b, where m is the slope and b is the y-intercept.
In this case, the slope (m) is -5 and the y-intercept (b) is 9. So we can substitute these values into the equation:
y = -5x + 9
To convert the equation from slope-intercept form to standard form, we need to eliminate the fraction by multiplying through by a common multiple of the coefficients. In this case, we can multiply through by 5 to eliminate the fraction:
5y = -5(5x) + 5(9)
5y = -25x + 45
Next, we rearrange the equation so that the variables are on one side and the constants on the other side:
25x + 5y = 45
The resulting equation, 25x + 5y = 45, is in standard form.