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Xy=10, 2( log 10^x - 1)= log 10^y
Joshua
answered2 years ago
oobleck
answered2 years ago
impatient much?
assuming the usual carelessness with parentheses,
2log(10^(x-1)) = log 10^y
2(x-1) = y
2(x-1) = 10/x
2x^2-2x-10 = 0
x^2-x-5 = 0
now solve with the quadratic formula.