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Hydrogen selenide (H2Se) reacts with water according to the following equation.

H2Se + H2O → SeH– + H3O+

In three to five sentences, identify the acid, base, conjugate acid, and conjugate base in this reaction. Use patterns in the periodic table to explain why the substances you identified acted as the acid and the base in this reaction.

is this right?
acid = H2Se
base = H2O,
conjugate acid = SeH-
conjugate base = H3O+.
Also, what are the patterns?

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2 answers

  1. H2Se + H2O → SeH– + H3O+
    acid = H2Se --right
    base = H2O--right
    BUT, you need to identify the PAIR.
    H2Se/SeH^- is one pair.
    H2O/H3O^+ is another pair.
    Generally those elements on the right of the table, i.e., N^3-, S^2-, Se^2-, Cl^-, act as bases.
    So if H2Se is the acid then SeH^- is the conjugate base of the pair.
    and H2O is the base so H3O^+ is the conjugate acid of the pair.

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  2. Thank you so much DrBob222, youre a great help

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