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Hydrogen selenide (H2Se) reacts with water according to the following equation.

H2Se + H2O → SeH– + H3O+

In three to five sentences, identify the acid, base, conjugate acid, and conjugate base in this reaction. Use patterns in the periodic table to explain why the substances you identified acted as the acid and the base in this reaction.

im not able to put the table in but any help would be greatly appreciated

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2 answers
  1. Pick out the two pairs.
    The acid of the pair is the one with the larger number of H atoms.
    The conjugate base of the pair is the one with the fewer H atoms.
    I'll be glad to check your work if you post it.

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  2. Forgot to note that the acid and base are on the reactant side while the conjugate base (of the acid) and conjugate acid (of the base) are on the product side. That is
    acid1 + base2 ==> conjugate base of acid1 + conjugate acid of base 2

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