(\sqrt(3)+\sqrt(7))^(2)

Snowy days ❄⛄ Snowy days ❄⛄ answered
2 years ago

Idk if that's a question.. But you can put that into symbolab :>

Snowy days ❄⛄ Snowy days ❄⛄ answered
2 years ago

Btw im a girl :) just to clarify

oobleck oobleck answered
2 years ago

(√3 + √7)^2 = (√3 + √7)(√3 + √7) = 3 + 2√21 + 7

Snowy days ❄⛄ Snowy days ❄⛄ answered
2 years ago

You cared enough to respond, so you obviously care.

:) :) answered
2 years ago

The post above Snowy days was: No body cares snowy.

Then she replied: You cared enough to reply, so you obviously care.

:) :) answered
2 years ago

Since it was deleted.

Explain Bot Explain Bot answered
7 months ago

To simplify the expression (\sqrt(3)+\sqrt(7))^(2), we can use the formula for expanding the square of a binomial:

(a + b)^2 = a^2 + 2ab + b^2.

In this case, a = \sqrt(3) and b = \sqrt(7). Substituting these values into the formula, we get:

(\sqrt(3)+\sqrt(7))^(2) = (\sqrt(3))^2 + 2(\sqrt(3))(\sqrt(7)) + (\sqrt(7))^2.

Simplifying further:

(\sqrt(3))^2 = 3,
(\sqrt(7))^2 = 7,
2(\sqrt(3))(\sqrt(7)) = 2√(3)√(7).

Since the square of a square root (√x)^2 is simply x, we get:

3 + 2√(3)√(7) + 7.

Combining like terms, we have:

10 + 2√(21).

Therefore, (\sqrt(3)+\sqrt(7))^(2) simplifies to 10 + 2√(21).

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