Consider 1.30 mol of carbon monoxide and 2.30 mol of chlorine sealed in a 6.00 L container at 476 oC. The equilibrium constant, Kc, is 2.50 (in M-1) for
CO(g) + Cl2(g) ↔ COCl2(g)
Calculate the equilibrium molar concentration of CO
(CO) = 1.30/28 mols/6.00 L = 0.00773
(Cl2) = 2.30/71 moles/6.00 L = 0.0054
...................CO(g) + Cl2(g) ↔ COCl2(g)
I...............0.00773....0.0054.........0
C...................-x............-x..............+x
E...........0.0773-x....0.0054-x...........x
Substitute the E line into the Kc expression and solve for x, then evaluate CO from 0.00773-x.
Kc expression = (COCl2)/(CO)(Cl2)
Post your work if you get stuck.
That's my response above with no name.
To calculate the equilibrium molar concentration of CO (carbon monoxide), we need to use the equilibrium constant (Kc) and the initial amounts of CO and Cl2.
Given:
Initial moles of CO (nCO) = 1.30 mol
Initial moles of Cl2 (nCl2) = 2.30 mol
Equilibrium constant (Kc) = 2.50 M-1
The balanced equation for the reaction is:
CO(g) + Cl2(g) ↔ COCl2(g)
Let's assume x mol of CO reacts to produce x mol of COCl2. Since CO and Cl2 have a 1:1 molar ratio, x mol of Cl2 will also react.
After the reaction, the moles of CO remaining will be (nCO - x), and the moles of Cl2 remaining will be (nCl2 - x).
Using the equilibrium constant expression:
Kc = ([COCl2]/[CO][Cl2])
Substituting the given values, we get:
2.50 = ([COCl2]/[(nCO - x)][(nCl2 - x)])
Since the initial moles of CO and Cl2 are greater than x (the amount that reacts), we can approximate (nCO - x) and (nCl2 - x) as approximately equal to nCO and nCl2, respectively.
Therefore, we can rewrite the expression as:
2.50 = ([COCl2]/[CO][Cl2])
2.50 = ([COCl2]/[CO] * [Cl2])
2.50 = ([COCl2]/[(1.30 mol) * (2.30 mol)])
Rearranging the equation and solving for [COCl2]:
[COCl2] = 2.50 * ([CO] * [Cl2]) / (1.30 mol * 2.30 mol)
Now, we substitute the values into the equation:
[COCl2] = 2.50 * (1.30 mol * 2.30 mol) / (1.30 mol * 2.30 mol)
Calculating the expression:
[COCl2] = 2.50 M
Therefore, the equilibrium molar concentration of CO (carbon monoxide) is 2.50 M.